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obsessedAndre
Registered User Posts: **240** Junior Member

"Find x > 3 such that

ln(x) < x^(0.1)"

How do you solve this type of problem? I plugged it into my TI-89 solver and didn't get anything. As a hint, the number is unbelievably huge.

ln(x) < x^(0.1)"

How do you solve this type of problem? I plugged it into my TI-89 solver and didn't get anything. As a hint, the number is unbelievably huge.

Post edited by obsessedAndre on

This discussion has been closed.

## Replies to: The Hardest Math Problem Ever

34Junior Memberbut yeah there must be a huge number greater than 3.05 that satisfies that equation, 'cept i have noo clue how to find it xD..

maybe there's a geometric sequence with the amount each value's increase is decreasing x__o if that makes anY sense..!

240Junior Member248Junior Member3,164Senior Member240Junior MemberJust in case anyone's panicking, this is way beyond anything on the SAT or SAT II.

777Memberln(5 X 10^15) = 36.14821...

(5 X 10^15)^.1 = 37.1447...

every number higher than that works too so i guess thats prolly not right

240Junior MemberThe actual answer is n => 3.431 x 10^15, so you're answer is correct although it is not the smallest correct answer. You got the decimal places right, though!

What made you think of anything x 10^15? Did you just guess and check?

119Junior Member3,164Senior Member777Membersorry i couldnt be of more help...i have no idea how to do it...it had to be a huge number so after i tried like 10000 i did like 50 x 10^10 no, 50 x 10^15 yay :p. i didnt know you needed the smallest number possible though

1New Member9New Memberx>11ln0.1/1-(0.1)^11

1New Member72Junior Member2New Member3.028777595