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student3737
Registered User Posts: **8** New Member

When an integer is divided by 5 the remainder is 3. What is the remainder when 4 times that integer is divided by 5?

ans is 2

ans is 2

## Replies to: Help with math 2?

1,186Senior MemberRemainder 3*4=12, 12/5 = 2, with 2 as remainder. so the answer is 2

6,355Senior MemberThe tricky part of this problem, at least for me, would be that using nice and neat algebra can trip you up. In the original equation, I = 5x + 3, the constant and the remainder are the same value: 3. In the new equation, 4/5*I = 4/5*(5x+3), the constant is 12/5, or 2.2, or 2 R2. So the remainder is NOT the same thing as the constant. Also, many will unthinkingly start with something like I/5 = x+3 which will start you off on the wrong foot.

150Junior MemberStep 2: Since 8 is the integer, multiply it by 4 to get the new integer and you get 32.

Step 3: Divide 32 by 5 and you get 6 remainder 2.

Step 4: Since the remainder is 2, the answer is 2.

An alternative way to do this would be to use algebra (set the integer to 5x+3), but there's no need when you can plug in a number that fits the description of the integer given.

464Member7,976Senior Member464Member