AP Chemistry 2008

proletariat2
Sun, 18 May 2008 10:22:55 +0000

Kaznack, it was Al^3+ + 4OH^- -----> Al(OH)4^-. Using six ligands is also acceptable if you change the charge to 3-. Luckily, I found that exact problem in my review book, but I still don’t understand why the aluminum hydroxide wasn’t solid considering that it’s insoluble.