BB page 746-747 # 12,14

AeroEngineer3141
Wed, 30 Jul 2008 21:12:15 +0000

747 #14

Questions 13 - 14 refer to the following functions g and h.
g(n) = n^2 + n
h(n) = n^2 - n
Which of the following is equivalent to h(m + 1)

Answer: A. g(m)


Substitute (m + 1) for n in the function h(n) = n^2 - n. h(m) = (m + 1)^2 - (m + 1).
Simplify it. h(m) = m^2 + m
If you refer back to the top, this is equilavent to g(n) = n^2 + n; therefore h(m+1) is equivalent to g(m).