Berkeley tougher than Stanford?

Gamma57722
Thu, 04 Aug 2005 22:27:10 +0000

As I said earlier, I performed the calculation by “weighting by percentage and assuming SAT distribution within each of the 100 point spreads is symmetric.” Under this directive, I multiplied the assumed average of each range (850 for 801-900, 1150 for 1101-1200) by the percentage of acceptees (18/1299 for 1001-1100, 404/1299 for 1501-1600) and summed. Sorry to cause confusion. Stanford provides precisely the same table and this method of computation, provided the limited data set, seems to minimalize unforeseen deviations in distribution. I’m interested to hear your response.