Blue Book, pg 361, help

DukeofFunk
Sun, 01 Jul 2007 14:42:49 +0000

Dunno if you need help, but as far as I can tell for 12 you have to do the problem with the rule that two sides of a triangle are always greater than the third side in mind. 3, 4, and 5 wouldn’t work because they’re all less than or equal to 7, but 6 would. Therefore, the answer is one possible triangle.

For 13, I can’t figure out any quick way to do it besides actually solving for x (-1, -5) and y (5, -7) and then adding all the possible numbers and knowing that 10 doesn’t exist. There’s probably a quicker way to do this, but I’m just too stupid.

For 14, since a multiplied by (b-a) is 0, then a must be 0. It wouldn’t matter whats in the parentheses, because whatever it’s multiplied by makes it 0, and since a is the number on the outside, it must be 0. Since a is greater than b, and a is 0, b must be less than 0. If b is less than 0, and a is 0, then a-b will be > than 0 because the two negatives would cancel out. Like, if b was -3, it would be 0-(-3), or 0+3, which would make it greater than 0. So all three statements are true

Did that help? Did you still need help? Am i too late? Is this confusing for you? Sorry. I hope I helped.