Bluebook, page 674 #19

somekidinnyc
Sun, 27 Jul 2008 21:30:05 +0000

x^-4/3 = 1/ x^4/3 and k-2 = 1/k^2 which tells us x^4/3 = k^2. Remember that taking the square root is like multiplying the exponents by ½. If we simplify the equation by taking the square root of both terms we find x^2/3 = k. If we do the same to y^4/3 and n^2 we get that y^2/3 = n.

So (xy)^-2/3 = 1/(x^2/3*y^2/3) and that means this equals 1/nk.

The answer is A.