Could someone explain this Math II Q. to me?

fiona_1
Sat, 04 Oct 2008 09:40:43 +0000

6 Brown-Eyed persons, 4 non-Brown-Eyed persons.
Chance that first person selected doesn’t have brown eyes = 4/10 = 2/5

Now since you picked one person without brown eyes, you have 6 BEP and 3 non BEP.
Chance that second person doesn’t have brown eyes = 3/9 = 1/3

Multiply them together, 1/3*2/5 = 2/15