how to find inverse?

ivyleaguewannabe
Tue, 24 Jun 2008 02:25:25 +0000

Amandeep1: this could be interesting because I don’t have my calculator with me right now. I might be able to walk you through it, but you are going to have to do the calculations!

When dealing with logs,subtraction indicates division. So:

log(z) - log(4) = log(z)/log(4)
log(z)/log(4) = 2
log(z) = 2log(4)
log (z) = (the solution to 2log(4))
When there is no base indicated, a base of 10 is inferred. So:
log “base 10” of z = the solution to 2log(4)
10^the solution should (hypothetically) = z

And you can always check your answer by plugging it into the original equation.

I haven’t done precalc/algebra II since school let out. I am a little rusty, but see if the above works!!