I forgot how to do this question.

crouch88
Tue, 20 Jul 2010 10:23:05 +0000

Damn dude, did you see collegeboard’s explanation? It’s ****ed up…

Okay, so if you wanna go with length= 4 and width= 2:

**Initial area **of rectangle= 4*2 = 8



The length of a rectangle is increased by 20%

**So, **length = 4 + (20% of 4)
Or, length = 4 + 0.8 = 4.8



the width of the rectangle is increased by 30%

So, width = 2 + (30% of 2)
Or, width = 2 + 0.6 = 2.6

New area of rectangle= 2.6*4.8 = 12.48

Increase in area of the rectangle= new area of rectangle - initial area of rectangle
= 12.48 - 8
= 4.48

**Now **you have the increase in area in terms of units.



By what percentage will the area of the rectangle be increased?



100% * (increase in area in terms of units / initial area of rectangle)
= 100% * (4.48 / 8)
= 56%

It would have been easier to calculate if I had taken L=1 and B=2…