November 4 SAT Math Level 1

hvgap
Sun, 05 Nov 2006 16:40:06 +0000

for the square one both squares had sides of 1, so that means from the centers to the edge both had edge length of .5, so then when they were side by side that is a total edge length of 1. I think i remeber the question asking how would you calculate the over lap if you knew the distance between the two centers was x, or something of that nature. So if the total distance between the two centers was 1 when they lined side by side that would mean that x would equal 1 in this instance and in order to find the overlap you would subtrat this from the total posible distance between the sides which is 1, so if the blocks were side by side the overlap would be 0, 1-1=0, so if they would overlapped a little x would get smaller but the total posible would remain the same so you could measure overlap by simple subtracting the distance between the centers from 1 so then you get 1-x.

I may be wrong but that was my logic behind it, oh and that one with the tri it was 2squreroot of 3, i got that by useing the law of sines, also if you think about the problem you can see that 120+120+120=360 (the angles of the actual hexagon) which means taht they could form a triangle if the points of the 120degree tri.s were lined up meaning that the area of those equal the area of the large tri.

Again i may be wrong but this is what i put and thought and it seems to make sense.

On the matrix one does anyone remember the numbers because i could sworn i got something like [-6,9] or something like that, im probaly wrong because i only did matrix’s when i was like 5 i think so i was pulling that outta my a*ss, i multiplyed the pieces of the first one by 2 before i subtracted each respected term from the 2nd matrix, on this one if im wrong i wont be surprised, but the answers from the 1 page of this thread were only like a digit off from mine so i just thought i would ask and make sure that the first pagers did not make a mistake or something.