One question for tomorrow's Math SAT.

Quicksandslowly
Fri, 22 Jan 2010 22:15:46 +0000

For x-axis reflection, put a negative in front of Mx, so it would be -Mx and a negative in front of B, so it would be -B. Thus, -Mx-B.

For y-axis reflection, put a negative in front of Mx, so -Mx. Thus -Mx+B.