PLZ help me with these crazy ap chem problems

It_sGr82BeAGator
Fri, 28 Sep 2007 16:42:50 +0000

Oh wait, I just saw that you added the 20%, but that’s still a little off because if you lose 20% of 257 you get 257-(51.4)=205.6 which is not equal to the 214.3 moles that you got earlier. The best way is to realize that 80% of the gas is kept and just divide by 0.8
And you forgot to divide the mass of the H2SO4 by 0.99 because it says 99% H2SO4 by mass.

So to do this problem
convert 4800m^3 to liters
divide by 22.4L/1mol to find number of moles of H2, multiply that by 1.25 to account for the 20% loss, set that number equal to the number of moles of Fe and H2SO4 you need, then convert from moles to grams for each reactant, remembering to divide by 0.99 for H2SO4 to account for the 99% mass