--SAT II MATH II Review Thread--

zoaxanthellae
Tue, 02 Jun 2009 23:23:33 +0000

^ I don’t think so; even functions are symmetrical about the y-axis. That is, the graph on the left side of the y-axis is the mirror image of the one on the right. You’ll notice that (1,2) is the mirror image of (-1,2); (4,7) corresponds to (-4,7). (0,4) doesn’t need a partner because it’s on the y-axis. Therefore, by changing that to (1,4), you move it to the right of the y-axis. Now that it does not have a “partner” on the left-hand side of the y-axis, the function is not perfectly symmetrical about the y-axis, and is thus not even. Make sense? :)

Side note: anyone know where I can find a realistic online Math II practice test? I haven’t studied for this other than looking over Sparknotes’ online stuff [which looks suspiciously easy] and want to know if I should do more. I’ve been an A-student in Pre-Cal, Trig, Geometry and most of it makes sense to me :/