FallenAngel9Posts: 2,429Registered UserSenior Member
I know I did (a) right. I think I did (b) wrong. I still don't know about (c) or (d).
****. I better get a 5 on this, or I'll be really mad. I was getting easy (and I mean easy) 5s on my practice tests, and in less time than allotted too.
2.
a) (E(7) - E(5)) / 7-5 = (21-13)/2 = 4 hund. of entries / hr.
b) ∫(0→8) E(t) = (2*4) + (3*13) + (2*21) + 23 = 112 hund. of entries
1/8(∫(0→8) E(t)) = 112/8 = 14 hund. of entries
1/8(∫(0→8) E(t)) represents the average number of entries, in hundreds, visitors deposited between noon - 8 PM.
FallenAngel9Posts: 2,429Registered UserSenior Member
This is going very wrong, very fast. Did part of (b) wrong, and I did (c) wrong; I did (d) right but since (c) was wrong that one is wrong too. This is not good.
I'm starting to get a little depressed now that I am seeing these. I know I got the concepts but I'm starting to think that the little things I messed up on are going to add up. I know I had to have aced the MCs though, so I don't know why I am worrying.
maybe im retarded.. but the question says "The number of entries in the box t hours after noon is modeled by a differentiable function E for 0£ t £8." , so how do you intergreate e(t), i think it should say E(t) is the rate of entries going into the box,
Replies to: 2010 AP Calculus AB Form A solutions (Official)
Action52, on calculator part, where the intervals are given, you just can write the answer.
****. I better get a 5 on this, or I'll be really mad. I was getting easy (and I mean easy) 5s on my practice tests, and in less time than allotted too.
a) (E(7) - E(5)) / 7-5 = (21-13)/2 = 4 hund. of entries / hr.
b) ∫(0→8) E(t) = (2*4) + (3*13) + (2*21) + 23 = 112 hund. of entries
1/8(∫(0→8) E(t)) = 112/8 = 14 hund. of entries
1/8(∫(0→8) E(t)) represents the average number of entries, in hundreds, visitors deposited between noon - 8 PM.
c) 112 - (∫(8→12) P(t)) = 96 hund. of entries
d) at t=9.183; the max occurs
and b) should be trapezoidal rule
am i retarded?
i really hope E(t) should be the rate.