# Welcome to College Confidential!

## The leading college-bound community on the web

Join for FREE, and start talking with other members, weighing in on community discussions, and more.

Also, by registering and logging in you'll see fewer ads and pesky welcome messages (like this one!)

### As a CC member, you can:

• Post reviews of your campus visits.
• Find hundreds of pages of informative articles.
• Search from over 3 million scholarships.

#### Top Forums

We've just launched our new college search tool at http://www.collegeconfidential.com/schools. Use this form to provide feedback as we continue to work toward a more robust solution to best meet your needs.

# 2010 AP Calculus AB Form A solutions (Official)

- Posts: 666 Member
edited May 2010
2010 AP Calculus AB Form A solutions.

Here are quick answers, let's check compare and check them.

1.
a) ∫(0→6) f(t) = 142.xxx cubic ft.

b) f(8) - g(8) = 48.417 - 108 = -59.58 cubic ft/hr

c) forgot already, but i did it

d) (∫(0→9) f(t)) - (125 + 108*2) = 26.335 cubic ft.

man it's so uncomfortable to write here, will add others later, or u guys can add too...
Post edited by webass on

## Replies to: 2010 AP Calculus AB Form A solutions (Official)

• Registered User Posts: 68 Junior Member
i disagree with d) the intergral should be 0 - 9 as the snow is falling the whole time?
• Registered User Posts: 242 Junior Member
Did you have to write +c for the "set up, but do not evaluate" problems to earn the point?
• - Posts: 666 Member
Action52, on calculator part, where the intervals are given, you just can write the answer.
• Registered User Posts: 2,429 Senior Member
I know I did (a) right. I think I did (b) wrong. I still don't know about (c) or (d).

****. I better get a 5 on this, or I'll be really mad. I was getting easy (and I mean easy) 5s on my practice tests, and in less time than allotted too.
• - Posts: 666 Member
2.
a) (E(7) - E(5)) / 7-5 = (21-13)/2 = 4 hund. of entries / hr.

b) ∫(0→8) E(t) = (2*4) + (3*13) + (2*21) + 23 = 112 hund. of entries
1/8(∫(0→8) E(t)) = 112/8 = 14 hund. of entries
1/8(∫(0→8) E(t)) represents the average number of entries, in hundreds, visitors deposited between noon - 8 PM.

c) 112 - (∫(8→12) P(t)) = 96 hund. of entries

d) at t=9.183; the max occurs
• - Posts: 666 Member
sh1t, i can't edit the 1st post...
• Registered User Posts: 2,429 Senior Member
This is going very wrong, very fast. Did part of (b) wrong, and I did (c) wrong; I did (d) right but since (c) was wrong that one is wrong too. This is not good.
• Registered User Posts: 68 Junior Member
2. d) should be 12 as p(t) is the rate so you dont do p'(t)

and b) should be trapezoidal rule
• Registered User Posts: 1,327 Senior Member
I'm starting to get a little depressed now that I am seeing these. I know I got the concepts but I'm starting to think that the little things I messed up on are going to add up. I know I had to have aced the MCs though, so I don't know why I am worrying.
• - Posts: 666 Member
FallenAngel9, I'm not 100% sure about (C), but 99% sure about others.
• - Posts: 666 Member
2. d) should be 12 as p(t) is the rate so you dont do p'(t)
Yes, find the max of p(t). You will get t=9.18xx
• - Posts: 666 Member
You know what, maybe you are right.
• Registered User Posts: 68 Junior Member
no at t = 12
• Registered User Posts: 68 Junior Member
maybe im retarded.. but the question says "The number of entries in the box t hours after noon is modeled by a differentiable function E for 0£ t £8." , so how do you intergreate e(t), i think it should say E(t) is the rate of entries going into the box,

am i retarded?
• - Posts: 666 Member
thats what i thought in the beginning, but then i found out in order to do part (a) we have to find E'(t), which there's no way to do it.

i really hope E(t) should be the rate.
This discussion has been closed.