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2010 AP Calculus AB Form A solutions (Official)

webasswebass Posts: 666- Member
edited May 2010 in AP Tests Preparation
2010 AP Calculus AB Form A solutions.

Here are quick answers, let's check compare and check them.

1.
a) ∫(0→6) f(t) = 142.xxx cubic ft.

b) f(8) - g(8) = 48.417 - 108 = -59.58 cubic ft/hr

c) forgot already, but i did it

d) (∫(0→9) f(t)) - (125 + 108*2) = 26.335 cubic ft.

man it's so uncomfortable to write here, will add others later, or u guys can add too...
Post edited by webass on
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Replies to: 2010 AP Calculus AB Form A solutions (Official)

  • ber1023ber1023 Posts: 68Registered User Junior Member
    i disagree with d) the intergral should be 0 - 9 as the snow is falling the whole time?
  • Action52Action52 Posts: 242Registered User Junior Member
    Did you have to write +c for the "set up, but do not evaluate" problems to earn the point?
  • webasswebass Posts: 666- Member
    ber1023, my bad. but the answer is still the same.
    Action52, on calculator part, where the intervals are given, you just can write the answer.
  • FallenAngel9FallenAngel9 Posts: 2,429Registered User Senior Member
    I know I did (a) right. I think I did (b) wrong. I still don't know about (c) or (d).

    ****. I better get a 5 on this, or I'll be really mad. I was getting easy (and I mean easy) 5s on my practice tests, and in less time than allotted too.
  • webasswebass Posts: 666- Member
    2.
    a) (E(7) - E(5)) / 7-5 = (21-13)/2 = 4 hund. of entries / hr.

    b) ∫(0→8) E(t) = (2*4) + (3*13) + (2*21) + 23 = 112 hund. of entries
    1/8(∫(0→8) E(t)) = 112/8 = 14 hund. of entries
    1/8(∫(0→8) E(t)) represents the average number of entries, in hundreds, visitors deposited between noon - 8 PM.

    c) 112 - (∫(8→12) P(t)) = 96 hund. of entries

    d) at t=9.183; the max occurs
  • webasswebass Posts: 666- Member
    sh1t, i can't edit the 1st post...
  • FallenAngel9FallenAngel9 Posts: 2,429Registered User Senior Member
    This is going very wrong, very fast. Did part of (b) wrong, and I did (c) wrong; I did (d) right but since (c) was wrong that one is wrong too. This is not good.
  • ber1023ber1023 Posts: 68Registered User Junior Member
    2. d) should be 12 as p(t) is the rate so you dont do p'(t)

    and b) should be trapezoidal rule
  • byuboundbyubound Posts: 1,327Registered User Senior Member
    I'm starting to get a little depressed now that I am seeing these. I know I got the concepts but I'm starting to think that the little things I messed up on are going to add up. I know I had to have aced the MCs though, so I don't know why I am worrying.
  • webasswebass Posts: 666- Member
    FallenAngel9, I'm not 100% sure about (C), but 99% sure about others.
  • webasswebass Posts: 666- Member
    2. d) should be 12 as p(t) is the rate so you dont do p'(t)
    Yes, find the max of p(t). You will get t=9.18xx
  • webasswebass Posts: 666- Member
    You know what, maybe you are right.
  • ber1023ber1023 Posts: 68Registered User Junior Member
    no at t = 12
  • ber1023ber1023 Posts: 68Registered User Junior Member
    maybe im retarded.. but the question says "The number of entries in the box t hours after noon is modeled by a differentiable function E for 0£ t £8." , so how do you intergreate e(t), i think it should say E(t) is the rate of entries going into the box,

    am i retarded?
  • webasswebass Posts: 666- Member
    thats what i thought in the beginning, but then i found out in order to do part (a) we have to find E'(t), which there's no way to do it.

    i really hope E(t) should be the rate.
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