<p>But hawkings, x = x, so they must have the same number of nines no matter how infinite they are, thats why I said theres an N amount of nines for “x”, which i have no idea what it is but it goes on forever.
(A calculator is never accurate, its just precise, you can ask any computer scientist, after all its like a computer and computers can only perform addition in terms of mathematics) another thing 0.33333… only approaches to 1/3. Because the notation of 0.33333… is more like expressed as an infinite series of 3/10^n where n = 1,2,3,4,…A where A approaches to infinity. And you know infinite series is still a limit so no matter how many decimals there are it will never be exactly 1/3 because it will go on forever rather it approaches to it. Otherwise how many decimals do u think there should be in order to be 1/3. Now, even if those two x’s dont have an N amount of nines, then the proof will still be wrong, because their substractions would not be defined or that 10x - x =/= 9.999…999…, rather 10x - x = 9.9999…#@$(@… All I’m saying is that that proof is wrong either way</p>