Calculus BC Answers

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<p>That’s what the image in the zip says as well. Sorry if it’s not clear, but it mentions -1<x<5 towards the bottom right of the page (and tests of endpoints are in top left).</p>

<p>now it comes down to whether the curve is nearer to 60 or nearer to 70…</p>

<p>MC is multiplied by 1.2?</p>

<p>sorry didnt look at the zip i was just reading what everyone was posting</p>

<p>It can’t go past 60. C’mon. '03 was a ridiculously easy test and the curve was, what, 64 for a 5…? Since this was a harder test, I’d imagine the curve would be more lenient? Yeah? Man. This sucks. I’m gonna end up with 4’s on all my AP tests, YET AGAIN!</p>

<p>what is the minimum for getting a 5 on the BC exam? like raw score</p>

<p>well like pollie says…usually is in the vicinity of 60-65. and shes right- the BC exam of 2003 required a raw score of about 64 for a 5. that exam was a cakewalk compared to this year’s exam.</p>

<p>lol…anyone else here still going to take calculus over in college even if they get a 5?</p>

<p>Gah… I can’t believe how many things I screwed up on this test. Going back over it now it really wasn’t that hard, or at least not as much as I made it out to be during the test. I just hope I got at least 20 - 25 points in partial credit for the free reponse and that the cutoff for a 5 is somewhere in the low-60’s.</p>

<p>you must be crazy, unless you go to a really prestigeous school</p>

<p>If I totally left 2 FRQ’s blank and screwed up totally one one of them, what’s the best score I can hope for? BTW, I left about 6 blank on the MC.</p>

<p>i think your taylor series forgot one term, it asks for 6th degree taylor polynomial so dont you have to go to n=6?? u stopped at n=4!</p>

<p>nvm nvm nvm nvm</p>

<p>collegebound123: that really isn’t that bad. assuming you got 3 of your FRQ completely right than you got 27 raw pts on that alone. if you only left 6 blank on the MC, that means you did 39 MC questions. using 2003’s curve…you would need to have 34 of those correct to get a five on the BC. now, if the curve is less than last’s year, you would need even less of your MC correct.</p>

<p>i’d say your pretty safe for a 4…you can definately hope for 5.</p>

<p>yeah if i at least got 30 MC questions correct, I think i’m okay for a 5. i have a feeling they will give lots of partial credit</p>

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<p>You start out at 0 and go to 5.</p>

<p>I screwed up on the first taylor series part…because i really misinterpreted the sentence about n being odd and derivative being 0…
algebra on interval of convergence was wrong…and I put radius of convergence instead (because that’s what I thought I read and for some reason if came out to be a radius)…I remembered absolute value signs! got part b.</p>

<p>q1 is completely right…as it probably is with most…
q3 I got right (I did it right anyway…not totally sure about answers)
parts a,b,c question 5 are right…part d I put no and ********ted an explanation…(from what I’ve heard they’ll give me a point for that).
q4…I messed up some…didn’t get part D…and god knows about euler’s method…should be ok…but I always make computational errors
q2 got part C…left the rest essentially blank</p>

<p>left 1 multichoice blank on calc section
2 or 3 on noncalc section and I know >for sure< I got at least one wrong…
which means I got more wrong too…let’s assume…well…I got 33 right on one of the practice ones (taking into account omits)…so lets assume that…would be a raw of 31…</p>

<p>am I ok? someone tell me I’m not going to die when I see my score…</p>

<p>ahh…long time no see cc…
haven’t been here since 2004 :stuck_out_tongue:
i def. screwed up my bc exam…too ashamed to tell my calc teacher that tho -<em>-…i said i did alright…
i think i’ll get a 4 max…T</em>T…
i completely got polar wrong…taylor series i had no idea about (the last two chapters on convergence and series, i failed to understand)…therefore, not knowing convergence, improper integrals, and series, half the non-calculator MCs went down the drain.
but
i’m glad it’s over…
now only satiis and ap chem and acts…</p>

<p>My interval of convergence was (-1, 5).</p>

<p>thats the correct interval of convergence…i had it essentially but then i simplified my absolute value incorrectly. that really sucks.</p>

<p>I have one BIG question concerning the last part of the last question of the free response, the taylor series one . . </p>

<p>To find the interval of convergence, one uses
lim n–> infitniy |an+1/an|, right? But the question says that all even derivatives=0, while odd derivatives follow some formula depending on n, so won’t an+1/an equal 0 because every other term in the series is a zero??</p>

<p>Also, one of the polar free response asked for the value of thetha when x-2
I did something with right triangle and got 44 something degrees. Is this right? How do you do it??</p>