<p>^If we accept that new condition, could it be 100-0-0-0-0? Pirate 4 has to accept 0 coins regardless because of what would happen if he and 5 were alone, and pirate 5 must do the same regardless because of what would happen at the 3-4-5 stage.</p>
<p>In bold are the “yes” votes.</p>
<p>Pirate 3 – 100
Pirate 4 – 0
Pirate 5 – 0</p>
<p>Pirate 2 – 100
Pirate 3 – 0
Pirate 4 – 0
Pirate 5 – 0</p>
<p>Pirate 1 – 100
Pirate 2 – 0
Pirate 3 – 0
Pirate 4 – 0
Pirate 5 – 0</p>