<p>some of it is…</p>
<p>is it just me or does it seem like the math sections were really hard? I left many blank in the student response questions.</p>
<p>I got 3 No Errors for the sentence correction questions. I believe one was about heat lightning, one was about some buildings going into some type of history thing, and I can’t remember the third. There is usually 2-4 No Errors in the section.</p>
<p>anyone know the typical curve on the SAT?</p>
<p>well…if u refer to ur blue collegeboard book…the scale conversinos part…it’s pretty blatant there…but i just recently found out tht collegeboard pre-gerenates the curves before we even take the tests…</p>
<p>so let’s say, if you miss around 2 math questions, what should your score be?
i have the collegeboard book but the range is so broad that you can’t really tell much from it.</p>
<p>this is for the pyramid question…</p>
<p>if e = m
e = one leg of pyramid
m = length of 1 side of base of pyramid
h = height</p>
<p>opp. the 30 deg of half a triangle for this = .5 m
opp. the 60 deg wud be h
opp the right angle wud be m</p>
<p>if .5m =x
and h = xroot3
and m = 2x</p>
<p>substituting would give you h = .5mroot3 or (mroot3)/2</p>
<p>where did i go wrong in this?</p>
<p>I believe the fourth CR reading section was about a man who heard a jazz pianist for the first time. Sound right?</p>
<p>I think that all of my college hopes came crashing down on Saturday …</p>
<p>I basically filled in the wrong section of the bubble sheet, which led to me messing up a whole bunch of questions. Yes i know, im stupid</p>
<p>for the question about the pyramid which i realized i got wrong after I walked out of the testing room:</p>
<p>You dont need to know the angle stuff, just that it is a right triangle.</p>
<p>(a)^2 + (b)^2 = (c)^2</p>
<p>c = m</p>
<p>b = (m*sqrt(2))/2</p>
<p>then you solve for a after plugging the stuff in</p>
<p>I thinkt he answers was like (m*sqrt(2))/2</p>
<p>how did u get any of that?</p>
<p>The answer to the pyramid one was m/root(2). It’s very hard to explain without pointing at a picture, but I’ll do my best. </p>
<p>Ok, you know the ‘edges’ of the pyramid are e, and the sides of the square base are m. First you need to find the slant height, which is the line that goes straight down the middle of a face of the pyramid, from the vertex to the midpoint of a side of the base (it is perpendicular to the side of the base). You can find this by using the pythagorean theorem, since e will be the hypotenuse of the right triangle, (1/2)m will be a leg, and the slant height (we’ll use x for now) will be the other leg. This gives us (1/4)m^2 + x^2 = e^2. Get x^2 by itself: x^2 = e^2 - (1/4)m^2. In the problem they tell us m = e, and they want h in terms of m, so substitute m in for e, giving us: x^2 = m^2 - (1/4)m^2. So that gives us our slant height squared- don’t bother taking the square root yet. Now, h, the height of the pyramid (what we’re looking for), is a leg of a right triangle with the slant height as the hypotenuse and half of a side of the base, (1/2)m, as the other leg. So using the pythagorean theorem, we use what we got for x^2 above for the slant height squared: h^2 + (1/4)m^2 = m^2 - (1/4)m^2. Get h^2 alone: h^2 = m^2 - (1/4)m^2 - (1/4)m^2. Combine like terms (I’ll do this in 2 steps so you see what’s happening): 1: h^2 = m^2 - (1/2)m^2. 2: h^2 = (1/2)m^2. Now take the square root of both sides: h = (1/root(2))m, or m/root(2).</p>
<p>I hope I explained that well enough.</p>
<p>wasnt the answer something like m(root3)/2?</p>
<p>Hey, anyone remember the logic question witht he four children (which one was the oldest)? Or was that experimental? Answer?!?</p>
<p>The answer to the logic question was the boy whose name started with “D.” I can’t remember his full name, since I made the diagram based on the first letters of the names.</p>
<p>The oldest kid’s name was Daria.</p>
<p>thanx, i think that was the only one i might have missed. what was the experimental math? I had too many math sections.</p>
<p>yea i remember it being daria who i think is a girl. it said she was one of the oldest. did anyone get the x^2/2 - 2x +k question ?</p>
<p>The answer was 30.</p>
<p>The experimental math section had a question about 24 teachers reading the National Enquirer.</p>