<p>I’m fairly certain as well.</p>
<p>the supposition was in the writing passage. to be honest, I cannot remember the exact context. I was fairly sure about it</p>
<p>Does anyone remember the QUESTION for the 2cx=y? I think I put -1/2 (because then -x=y) but I’m just now starting to think it asked for which is “not possible if x is not equal to y,” where the double negative screwed me over and is going to drop me from a 2400. Efffffff…</p>
<p>Yeah, it was asking for the equation that wouldn’t work if x=/=y. The answer was 1/2.</p>
<p>0 is wrong right? </p>
<p>yeah, its 1/2 for sure</p>
<p>definitely 1/2</p>
<p>Uh so people are saying the question about the line segment being reflected across the y-axis is only 2 points of intersection? What?</p>
<p>People think that an intersection = two lines touching each other and continuing on.</p>
<p>However, intersections are literally any shared point between two lines (even if that point is an endpoint). The answer is 3. </p>
<p>The problem is that I don’t remember the problem well enough to give input. I just remember reflecting it across the y-axis and finding the answer to be obvious: 3.</p>
<p>Yeah that was undoubtedly 3. The intersections weren’t even endpoints lol.</p>
<p>If people are saying two, they probably missed the intersection along the Y axis.</p>
<p>That’s the thing immasenior, I don’t even remember any intersections being endpoints. And if they did intersect at endpoints, and shared points don’t count as intersections (as they do) wouldn’t that make the total number of intersections 1, not 2, as everyone is claiming? Whatever, it’s 3.</p>
<p>I don’t recall if it was symmetrical. However, I do recall marking each vertex of the graph on its (-x) value. It is 3.</p>
<p>Wouldn’t it have to be symmetrical by virtue of being a reflection?</p>
<p>I was talking about the initial function and if it was symmetrical about the y-axis. If it was, there would have been two endpoint intersections. I worded it terribly. I don’t know how I cam up with “I don’t recall if it was symmetrical”. I meant “I recall that it wasn’t symmetrical”. This confusion is unnecessary for a settled problem lol</p>
<p>Ok yea.</p>
<p>I was hoping this thread wouldn’t die before February 13th… Oh well</p>
<p>Hey, I’ll still be responding for the foreseeable future…something’s gotta hold my attention until the 13th.</p>
<p>Same here. I almost want people to tell me I’m wrong about something.</p>
<p>You got every question wrong.</p>
<p>But yeah in all seriousness, I know what you mean. Now’s right around the time that I get really irrationally paranoid that I filled out the answer sheet wrong or something stupid like that.</p>