<p>Yea, well I have the updated book of Direct Hits along with Barron’s SAT Vocab flashcards, so I’m kind of overwhelmed, I don’t know what to study in terms of vocabs…
I plan to read through the book but actually use the flashcards to study vocabs. </p>
<p>To check for intersections, you would basically perform a horizontal line test, check to see where two points had the same value, and if those values were equidistant from the origin in terms of X values, then you would have “same points.” For those of you saying 1, 2, or 3, is that what you did? </p>
<p>^yeah. </p>
<p>Yeah, I did the same and got 1. </p>
<p>No, I just drew the reflected graph. There were clearly 3 places of intersection.</p>
<p>@WorkSAT2014 An intersection is any shared point between two functions. The horizontal line test is not necessary. It’s as simple as literally looking at the two graphs to see where the two lines intersect. There’s no way it could be one lol. </p>
<p>a rough estimate of the function (no matter how you draw it though you’re going to get at a minimum two intersections. But I clearly remember the answer to this being 3 on test day):
i.imgur.com/8Q0ela5.png</p>
<p>It’s either 3 (most likely) or 2. It cannot be one. Can we please stop discussing this now? </p>
<p>@relativelysmart that was definitely not the graph. I understand where you guys are getting 3 from but if you looked at the graph, one of the values was 5 coordinates away from the x axis (left side) and one was 4 (right side), so they looked close enough to be intersections but they were in fact not. </p>
<p>^agreed.</p>
<p>How about waiting for 4 more days and then looking at the correct answer guys? </p>
<p>I’m worried about my essay… I know that I nailed the multiple choice, but I only wrote a little less than a page and a half. I also used two fictitious examples. However, they didn’t sound too outlandish. I interspersed some SAT words here and there in attempt to bolster my score, but I doubt that I got much higher than a 9. Does anyone have some prior knowledge about this? This was my first “real” SAT. </p>
<p>In addition to the point on the y-axis, I found two points where a -x value (definition of reflection over y-axis) yielded a pair of coordinates still on the original graph. </p>
<p>^ well both the x and the y coordinates have to be the same and only the point (0,1) was common in both graphs. </p>
<p>I am aware. I tested specific values and found three points of intersection. I posted an image of the graph earlier in the thread. It is reasonably accurate.</p>
<p>Pusat, wherever the two graphs crossed each other is a common point lol. The answer is without a doubt greater than 1. </p>
<p>I’m with immasenior.</p>
<p>@relativelysmart i agree that intersections = same point. However, I just didn’t see more than one intersection when I redrew it.</p>
<p>Also, when scores come out, can someone post what the correct answer was. I won’t know because I missed another question (the question about the lady who retires at 70…but idk if that was experimental or not)</p>
<p>How did that question go, WorkSAT2014? I don’t really remember that one. </p>
<p>PusatShrade, you have a fundamentally flawed understanding of what an intersection is. Just because (0,1) was the y-intercept on both graphs does not mean it was the only intersection. An intersection is a point common to two lines or line segments. There were unequivocally three of these. Like, I drew it out and there were clearly 3 intersections.</p>
<p>I don’t understand how people are still not understanding this.</p>
<p>I remember worksat’s question. So she can only retire when years worked and age add up to 70, I believe. She also had to have worked a certain minimum number of years at the company. I don’t remember her initial age or years worked, but I think the answer is 8.</p>
<p>Ckoepp127 are you aiming for a perfect?</p>
<p>@ckkoepp127 Yeah, the answer was 8. I agree with your definition, but I don’t agree with your graph. But I am starting to lean towards 3, simply because of the number of people who believe it is 3 and because of the fact that CCers are rarely incorrect. </p>
<p>Definitely 3
Did anyone get an experimental math section with a question on minimizing amount of steel for an open top cylinder?</p>