<p>25% H, 75% C, CH4</p>
<p>and it was X(OH)2</p>
<p>yes to your first question. CH4 was the answer to an empirical formula problem. I dont remember any lead hydroxiide though sorry.</p>
<p>clicheusername, I got CH4 for one of the precent mass ones it was like 75% carbon 25% hydrogen or something like that and i don’t remember the Pb one</p>
<p>I got the Pb(element)2(OH)3… i think… well somehting with an OH at the end. 
lol</p>
<p>What was the Pb2(OH)3 question??</p>
<p>I got CH4 for the empirical formula one.</p>
<p>They might be thinking of Cd(OH)2.</p>
<p>And something never should be X2(OH)3. That’d mean X has an oxidation state of 1.5+</p>
<p>Oh, I’m talking about Cd(OH)2… idk what you guys are talking about… a reaction maybe?</p>
<p>do you guys remember graphs?
V and T = straight line w/ positive slope
V and P = decreasing curve ?
last graph (dont remember) = increasing curve ?</p>
<p>it might have been Pd or Cd, its molar mass was low 100’s i believe… i d ont remember the question though sorry, i’ll think of it</p>
<p>On one of the graph questions, it was the concentration of product as the reaction reaches equilibrium. I put the graph that started at zero, increased, and remained constant. Agree anyone?</p>
<p>Haha ok… I have no recollection of that whatsoever.</p>
<p>what was the answer to the q dealing wit CS2 + O2 —> ?</p>
<p>It was within the set of questions Kerri was talking about… PV, VT, etc.</p>
<p>for CS2 question, it forms 1 mol CO2 and 2 mol SO2</p>
<p>rb9109 yeah thats what I got for the last one =)</p>
<p>yeah, that’s the right graph rb9109 because the concentration of the products starts at 0 since the reaction hasn’t happened yet and then it increases until equilbrium is reached.</p>
<p>was that the one that had to do with a substances solubility as temp increased or was that something else</p>
<p>What was the most difficult to oxidize or something? Was it F2?</p>
<p>i said F2 i think</p>
<p>No, this was one of the early “matching” questions with the graphs.</p>
<p>And I also put F2 as most difficult to oxidize. My reasoning: have never seen F with positive oxidation number; H2 has reduction potential of 0 V, so could be oxidized. Other choice I considered was C - could be, but most likely F2</p>