June 2010: Math II

<p>@wang </p>

<p>i edited and quoted that. read the explanation at the bottom as to why that is probably not what the question asked.
the 0.05 degree error was made from the center of the disk not the edge</p>

<p>the angle used to find the final answer is 0.05 degress not arctan(50/1188800)+0.05</p>

<p>Does anyone know a way to do the ln(x) = e^-x question without plugging in the answer choices? I got 0.27 by guess and check.</p>

<p>Also, was the parametric question = -1/3</p>

<hr>

<p>Yea all you had to do was graph it on your calculator(set mode to parametric) O.o question was pretty easy</p>

<p>I just found it odd that he would aim for the bottom. Wouldn’t the point of shooting a laser at a point be to try to HIT THE POINT?</p>

<p>@fresh-man - i graphed both and found the intersection. i forget the answer, but i’m pretty sure that’s the right way to do it?</p>

<p>No. There’s no algebraic way that I know of. I spent about 5 minutes trying to find an answer algebraically but I just used my calculator and checked the y-coordinate of their intersection.</p>

<p>no, it was asking for what lnx was when y=0. Which meant you find the x-intercept and plug that value into lnx.</p>

<p>Also, the one with the 5^2x+1=96.
I had NO idea how to do that. And I’m guilty of calculator-bashing on it; I just saw that 96 is between 25 and 125 (not too hard to do), so I just thought 2x+1 is a little less than 3. So I got .8 something? I think?
I got a flat 96 when I plugged it back in for x…</p>

<p>^Lol. Why didn’t I think to graph it? I’m really bad about using my calculator. Thanks for the clarification on the parametric. I solved that algebraically :(</p>

<p>Does anyone remember about what # these questions were? Were they around 46-49?</p>

<p>1) series question
2) f(3) - f(1) question
3) angle made by lines</p>

<p>I’m trying to figure out what I skipped.</p>

<p>@RustGust - it’s just logs, isn’t it? log96/log5 = 2x+1, find the logs on the calculator, and solve, i think.</p>

<p>@ luminouzz

  1. 2-1/n
  2. 6
  3. 9… degrees
    i answered #1,2 above somewhere</p>

<p>^Thanks, but I was trying to figure out what # these questions were. I know I skipped three around 46-49.</p>

<p>1) series question
2) f(3) - f(1) question
3) angle made by lines</p>

<p>@luminouzz
2) f(3) - (f1) = 6
3) angle made by lines 9.16 = arctan(3/5)-arctan(2/5)</p>

<p>Series is somewhere in the 30s, f(3) - f(1) is 48, angle is 47</p>

<p>^he’s BS’ing us.</p>

<p>@driftwood
Probably. I know how to manipulate logs but I thought of taking log5 of both sides but I couldn’t find how to adjust the base of the log on my calculator. Stupid TIs.
I didn’t care enough about the question to go through change of base and stuff, and didn’t know that I could just do what you said :X</p>

<p>Mah bad lol.</p>

<p>@RustGust - actually you first ahve to make it log596 (where 5 is a subscript) = 2x+1, and for change of base you just do log base 10 of the non-subscripted one over the subscripted one. that’s the only way i can remember it - the one that’s already sort of “above,” because one is subscripted, goes above again.</p>

<p>RocknPiano: Who’s bsing us? He seems right. I was asking about the number of the questions, not the answers to the questions :slight_smile: Trying to figure out what I skipped.</p>

<p>tbh, I think that he’s right about #48.
I remember the f(3)-f(1) being close to the bottom of the page, with one or two questions after it. <em>shrug</em></p>

<p>@ Luminouzz
Yes i’m pretty sure i’m right about 47 and 48, cuz i know i skipped 48</p>

<p>I think RocknPiano thought that the other guy thought the answer f(3)-f(1) was 48, rather than saying that the question was number 48 on the test.</p>