<p>how did you get 101??</p>
<p>yea i put 50</p>
<p>did you get the grid in for:
f(x)=(x-2)^3 + 5?</p>
<p>101 is the equilateral triangles one.</p>
<p>50 is the adults leaving the room one.</p>
<p>What was the one like 9 kids in math and 10 in a dfifferent club and how many are only in math or somethiing? 4 ?</p>
<p>For the 1 w. the cube in no paint, was it 16?</p>
<p>mirage i plugged that into the calculator lol</p>
<p>ariger, what was the answer?
And the cube one was 8.</p>
<p>f(x)=(x-2)^3 + 5?</p>
<p>2</p>
<p>mirage what was the question for the function u wrote, i forgot</p>
<p>I put 8 for the cube with paint.</p>
<p>yepp, thats the answer that I got.
I’m pretty sure it’s right.</p>
<p>yea the answer to that was 2</p>
<p>yeah i got 2.</p>
<p>ariger, i don’t remember… hipster, you got 2-- do you remember what the question was?</p>
<p>i know… i don’t get this thread… did i had a totally different SAT test?</p>
<p>well i got 2, too…</p>
<p>It was, what x value would make f(x) equal 5.</p>
<p>how the heck did u guys get 101? i got 150 for the equilateral triangles, as 3 sides of 8, so you need 50 times 3 to get 150</p>
<p>“i know… i don’t get this thread… did i had a totally different SAT test?”</p>
<p>There are two different tests and 3 different experimental sections (section 4 was experimental).</p>
<p>oh yea (2-2)^3 + 5 = 5 lol
101 for the sticks. 3 for the first one, and then you use two sticks for the other 49
so 2(49) + 3</p>