<p>i had four math sections. and I’m sure section 6 was my experimental.
So if that question was in section 2, then no. </p>
<p>And the kid question-
answer, I believe, is 50.
99 adults, 1 kid.
2% = 1/50
So then you’d need 1 kid and 49 adults
Therefore, 99-49 = 50
50 adults leave the room.</p>
<p>For the perpendicular line section, it was 3x/2y and yes, the answer was 1.</p>
<p>HopefulCEO</p>
<p>it was 3x/2y or 3y/2x. either way it was 90/90 = 1</p>
<p>99-50</p>
<p>=49</p>
<p>1/49 doesnt equal 2%</p>
<p>^ but you have to add in the kid.</p>
<p>amonkeydotnet - how do you know section 6 was equating?</p>
<p>The question read there are 99 adults in a room and 1 kid. How many adults should leave for there to be 2% kids.</p>
<p>i dont get why its 50 adults</p>
<p>oh… now i get it…</p>
<p>AH!!!</p>
<p>i don’t remember sections. Only problems.
I’m sorrrry.</p>
<p>okay.
if 49 people leave the room, then 99-49 = 50 ADULTS are left, right?
So then you have to add the child in. 50 adults + 1 person = 51 people total. But 1/51 people isn’t 2%
Take out one more adult, and you have 49 adults and 1 child which is 50 people.
1 child/50 people= 2%</p>
<p>Does that make sense?</p>
<p>the question stated that the first was 3000 miles and each one after it was 5000 miles, therefore, you want to subtract 3000 from all of the answer choices, and see which one is a multiple of 5000. 43000 is the only one.</p>
<p>amonkeydotnet is correct here.</p>
<p>this SUCKS!</p>
<p>I missed that question too. D:
But I got 51. xD</p>
<p>well that could have been an extra point for my raw score
:(</p>
<p>Wait, did the math section also have two different versions?
I didn’t get any of these problems you guys are talking about…</p>
<p>yeah, I went from thinking I had an 800 to -2…CC is probably the cause of widespread depression for the general high school population :(</p>
<p>For people who had 4 math sections, in this order, math 2, 5, 6, and 9. With problem x-y=y-z=z-t=5 as second to last in section 2, and the red/white cube question in section 6.</p>
<p>Was section 2 or section 6 the equating section?</p>
<p>who had the most money (or whatever)
**
AMY?</p>
<p>**</p>
<p>I had an experimental writing section so based on your description I would say section 6 because I did not have a cube question but I did have the question you described in section 2.</p>
<p>Thus I believe the section 6 math was your experimental</p>
<p>yes, it was Amy</p>
<p>Okay so I had math for 2,3, 5, and 8. How many of you had a section where the last problem was the letters/numbers combination that could be done 70 different ways or something along those lines? I don’t quite remember it I just remember the answer choices were like (70^6) - (70^4) and (70^2).</p>
<p>^The answer is 70^2; at least that’s what I think I put.</p>