Math for March SAT 2009

[rj42492]

<p>I know I’m a little late here, but the function described in the f(ab) problem can actually be written as a function of x. f(x)=6ln(x)/ln(2) OR 6log2(x). </p>

<p>Its defined for all x>0, and actually works within the confines of the problem. I thought this was kind of interesting. It can be justified simply for x=2^n, for rational n, and with a more complex argument, for all irrational n, which allows you to have all x>0 (2^log2(3) to get x=3, for example). Obviously not that important to the question itself, but I found it kind of interesting.</p>

[bsDBer2010]

<p>HAHA major props rj42492!!! I just checked it on my calc; I did figure it would have to be some weird log/ln problem, but wow u did it!</p>

[rj42492]

<p>Thanks! It occurred to me last night at like 3AM, and I figured I might as well post it here, in case anyone still wanted to maintain that the problem was invalid.</p>

[canned_dice]

<p>Holy cannoli.</p>

[Monoclide]

<p>

I know I’m a little late here, but the function described in the f(ab) problem can actually be written as a function of x. f(x)=6ln(x)/ln(2) OR 6log2(x).</p>

<p>Its defined for all x>0, and actually works within the confines of the problem. I thought this was kind of interesting. It can be justified simply for x=2^n, for rational n, and with a more complex argument, for all irrational n, which allows you to have all x>0 (2^log2(3) to get x=3, for example). Obviously not that important to the question itself, but I found it kind of interesting.

</p>

<p>A perfect example of 9th grade math!</p>

<p>Just kidding. Excellent work. :)</p>

[ro51092]

<p>Can you explain the 2p<x<3p question?</p>

<p>Why is it 40-50? I plugged in 13 for p, and so x was between 26 and 39. </p>

<p>26+39=65.
100-65=35
x=35
26<35<39</p>

<p>Unless I’m missing something?</p>

[4.0]

<p>If p = 13 than 3p = 39</p>

<p>I don’t know where your numbers came from but since there was a circle 360 - 3p = x</p>

<p>so x = 321</p>

<p>321>39</p>

<p>Unless you’re talking about an experimental problem which I didn’t have.</p>

[MasterFox72]

<p>Guys I don’t get why the circle one was not 2root2 can someone explain?</p>

[bannas200]

<p>In response to 4.0, the circle was in percentages…i interpreted it as a pie chart…with a total of 100%</p>

[canned_dice]

<p>3p+x = 100</p>

<p>3(13) + x = 100 , thus x = 61</p>

<p>61 > 3(13), so thirteen can’t work</p>

[cHrOn1c]

<p>Perimeter of triangle was 21? not 15?</p>

[bsDBer2010]

<p>^asked for the difference between the two perimeters:
21-15=6</p>

[ro51092]

<p>5h1+.</p>

<p>there goes my 800.</p>

[retrospectively]

<p>dammit, i thought they were asking for p for the p/x problem, i put 14 or 17 or something. @___@</p>

[Bob.Dylan]

<p>Anybody know what score I would get with one wrong, everything else right? Like a 780?</p>

[IlikeRice]

<p>i think we need to call cc and tell them the test was design bad that sum questions may had multiple answer and stuff >.> and yea 1 wrong is a 780 on a normal</p>

[dividebyzero]

<p>IlikeRice, I don’t think it was that ambiguous. We’re just being desperate, lol.</p>

[andrewc92]

<p>2y< x < 3y
How can it be 49?
This was referring to percent right?</p>

[MasterFox72]

<p>How much do you think I’d get with two wrong? (stupid math and science kid one and the 2root2 forgot to multiply by 2 for diameter)?</p>

[jules92]

<p>andrew -that question showed a pie graph and there was 1 a and 3 ps, it wasn’t drawn to scale … sooo a + 3p = 100%</p>

<p>if a = 49
then to get p you do 100 - 49 = 51
p = 51/3 = 17</p>

<p>2p = 17<em>2 = 34
3p = 17</em>3 = 51</p>

<p>2p<a<3p
34<49<51</p>