<p>I don’t think so…and not experimental…</p>
<p>^ no, i think we’re talking about a different question. I don’t remember a question like that.</p>
<p>lol yeah the fill-ins were a pain I skipped 3 =/</p>
<p>argh what was the question???
wasn’t it like the square of x and y equals something…</p>
<p>Was it x^2 + y^2 = x^2 - y^2 ?</p>
<p>Definatly not…</p>
<p>I’m fairly certain it was (X + Y)^2 = X^2 + Y^2
It is possible I misread the plus sign… I don’t think so.</p>
<p>^nahh i don’t think it was that
I don’t remember solving a problem like that
and if that was it, then the X^2 and Y^2 would cancel out and you would end up with 2xy=o</p>
<p>No, thequestionmark has the right question. pigs<em>at</em>sea – exactly. It comes out to 2xy=0. Thus, the answer to the question was either x or y = 0</p>
<p>^^ Yeah, you did end up with 2xy = 0, which is why the answer was x=0 or y =0. I vaguely remember it being C, although I’m not sure.</p>
<p>was that from the experimental section?? because i didn’t have that question.
but what were the other answer choices?</p>
<p>It was a real question. I didn’t have math experimental and I had that question. I think that answer was C. Choice D was x or y = 1 and I think E was x or y = 2 or something. The other 2 answer choices were x=y and something else.</p>
<p>Oh yeah, I think a and b were x = y and x = -y. Then it was definitely C</p>
<p>^nope, pretty sure that the question wasn’t (x+y)^2=x^2+y^2…i remember an integer in that equation</p>
<p>I’m positive that was it although they stated it in words, not as an equation so that’s how you may have misread. I misread too at first, but it said that the square of x and y is equal to the square of the sum of x and y.</p>
<p>for the parabola graph one where they give u a point (1,6) and they give you an equation for the function f(x)=a(x+b)+something, you plug in the point and solve for like a variable then you plug it back into the equation, and the answer wasn’t just that x=-3 or something because a is positive because the graph opened up, BUT h was NOT negative because the y intercept was NOT negative. It didn’t even show the y intercept on the graph. The left side of the graph was going up.</p>
<p>^^ Maybe you’re thinking of the wrong question, but the parabola one where the answer was x = -3 was opening donward and its vertex was below the x axis.</p>
<p>^ ?? (responding to pig)</p>
<p>The parabola was facing down with a negative y-intercept… Unless we’re talking about something else. </p>
<p>And the question was definitely x^2 + y^2 = (x + y)^2
And the answer was definitely x=0 or y=0. Process of elimination or simply solving it out would have given you that.</p>
<p>holy crap
i am so confused
ok i need to stop worrying and just wait until april 7th
they don’t send you a score report telling the questions you got wrong huh?</p>
<p>Agreed, with theperson1.</p>
<p>Y = ax^2 +b (in this case a is negative)</p>
<p>The movement was in the y values. I do not remember what I got, but the process was adding the initial b in the function to the negative b</p>
<p>I’d like to know that as well. ^ Unfortunately I’m stressing over this math section as well. I never expected that I’d skip so many questions :((</p>