<p>Dude, I don’t think anyone remembers the numbers, maybe the first couple of the last couple.</p>
<p>It is 1/4. Let’s say he had 12 dollars. He spent 1/4, or 3 dollars and have 9 left. Spent another 1/3, so he has 6 left. He used 3 for the trip. That’s what the question asked, not what he had left.</p>
<p>^do you remember the whole question? i want to see where I messed up…i’m at -3 now T-T</p>
<p>Can someone explain to me why the last one was what it was? (b^2+b one) Because I tried doing it with all the values by substituting numbers in… and none worked!</p>
<p>I think I’m gonna go crawl in a hole and cry myself to sleep for missing easy questions.</p>
<p>Viggy:
He had money
He spent 1/4 on it on something neat
He saved 1/3 of what he had left
What is that amount? </p>
<p>1/3 of 3/4 is 1/4.</p>
<p>the coordinate question:
b, b^2
b^2, b^4</p>
<p>substitute 6 in
slope equation rise/run</p>
<p>6^4-6^2 over 6^2-6
you get 42=6^2+6. I don’t know why substituting didn’t work for you there.</p>
<p>that list needs to be updated. question with the answer of 7 was how many perfect squares are in between 50 and 200 or something like that…there are 7 of them.</p>
<p>for the grid in of 6: the question had 3<2x<11, what was 3x. other possible choices were 9 and 12.</p>
<p>the running question with the ratio needs to be added to the list. The answer was 3:2</p>
<p>there was a absolute value graph in which the answer was D.</p>
<p>and the one with x = 8 and y = 16 remember the question asked which of these don’t fit the equation y^2 = x + x + x + x or something</p>
<p>what do you think
2 missed grid ins
3 missed MC
and 1 omitted will be?</p>
<p>it was a factoring question.</p>
<p>(b, b^2) (b^2, b^4)</p>
<p>m = b^4 - b^2 / b^2 - b = (b^2 -b)(b^2+b) / (b^2 -b) the b^2 -b cancels out, so you get b^2 +b</p>
<p>what was the x=8 y=16 one?</p>
<p>Ktk got it.
Does anyone remember the question:
[|a|b|c|]
ANSWER: 232 223</p>
<p>wait, coolducks…for the one with 7/8 i think i may have done the same mistake as you did. I got: one point is 1/2 the other is 2 (or 4/2) so the midpt is 1.25, then do 1.25 - .5, which gives you .375, and add that to .5, which gives you .875, or 7/8…I just did 1.25/2=.625 + .5= 1.125, but thats wrong</p>
<p>the constant for the parabola was 3/4</p>
<p>1.25-.5 = .75 … divide that by 2 and it gives you .375* sorry</p>
<p>
OK, but let’s say you substitute 2 in for b.
so (2)^2+2=6.
graphing 6x yields (2, 12) and (4, 24)… which is NOT correct for (b, b^2) and (b^2, b^4)…</p>
<p>For the water changing one that apparently is</p>
<p>1:04 to 1:08</p>
<p>Is that during the rapid increase in the beginning of the graph?</p>
<p>wow…do people score higher in M the second time around? because i really messed up this time…3 errors on easy q;s…T-T</p>
<p>you weren’t supposed to worry about values. factoring was the way for the solution iirc.</p>
<p>I omitted 2-3. so I hope my accuracy was spot on. Ran out of time…</p>
<p>
But if it doesn’t work with REAL numbers… then what’s the point?</p>
<p>EDIT: NVM I understand now…</p>