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<p>(Speed1<em>speed2)/(Speed1+speed2)
Is used to determine the distance.
6 is the Peter’s speed for walking (6 mph) 30 is Peter’s speed for biking (30 mph)
(6</em>30)/(6+30) = distance.</p>

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<p>(Speed1*speed2)/(Speed1+speed2) = distance</p>

<p>What about </p>

<p>(2 * speed1 * speed 2) / (speed1 + speed2)? Isn’t that average rate?</p>

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<p>Walk=10m
Bike=2m</p>

<p>Walk + Bike = x
10m + 2m = x
12m = x</p>

<p>x = 60 m</p>

<p>60/12 = 5</p>

<p>Not sure where I got the logic from, but it works! :D</p>

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<p>umad?--------------</p>

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<p><a href="Speed1speed2">quote</a>/(Speed1+speed2)
Is used to determine the distance.
6 is the Peter’s speed for walking (6 mph) 30 is Peter’s speed for biking (30 mph)
(630)/(6+30) = distance.

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<p>Where’d you get 6mph and 30mph…I thought it was 10 and 2, respectively.</p>

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<p>^ he went ahead and converted the miles per minute to miles per hour (1mi/10min –> 6mi/60min)</p>

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<p>Wow guys, thanks. -____________________________-"</p>