<p>sherwin, what do you think about the P and V question? PV-const or P/V-const?</p>
<p>PV = constant, because that’s the definition of inverse proportionality.</p>
<p>As one goes up the other goes down.</p>
<p>I believe I put 49 for the argon problem if you can tell me some more about it I might remember.</p>
<p>I also put PV using the ideal gas law and crossing out hte constand and i put 49 but i was unsure if it was correct</p>
<p>Of course it’s PV. i’m the stupidest person in the whole universe!!! I knew it and still got it wrong! Anyway!</p>
<p>For the AR Q: A) 4,4 B) 22,4 C) 49 …that’s all i remember</p>
<p>choice D was 98, but it was definitely wrong</p>
<p>Have you taken the chem test before? How do you find this one copared to past tests?</p>
<p>hey what is the minimum row score for 800 on SATII chemi?</p>
<p>i did not take the Chem SAT II, but this had some questions that were easier than review books other questions that were much harder!</p>
<p>10 Real SAT’s indicates that you can omit upto 7 for an 800, Kaplan allows you to omit upto 5 for an 800, but said that there have been administrations of the Chem SAT II which have had a curve that has been generous enough to allow upto 10 incorrect answers for an 800 (but I think they mean 10 omissions). Hopefully the curve will be 77+/85 => 800, or something good like that.</p>
<p>Oh I think copper-sulfate is blue.</p>
<p>Yes CuSO4 is blue</p>
<p>Greenhouse one was TT</p>
<p>wut about the one with which does not conduct electricity? was it molten sulfur or .1M of sr nitrate??</p>
<p>oh and which of the metals or something forms to produce fats ? it was K right?</p>
<p>but the polar molecule should be xH3, just like NH3</p>
<p>Molten sulfur. Nonmetals are poor conductors.</p>
<ol>
<li>Kinetic molecular theory: Answer was A. The KMT does NOT state that molecules lose KE upon collisions.</li>
</ol>
<p>anyone remember anythign else?</p>
<p>did u guys have a couple of TT CEs in a row?..heh…eek</p>
<p>no, i had 2 in the first colunm and another 2 in the second one</p>