<p>would getting a raw score of 28 out of 50 break 650?</p>
<p>I omitted 8 qs and was unsure on about 10 of them, what do you guys think my overall score would come out to be?</p>
<p>4 numbers: 3 are same. Thus, u have {a, b, b, b}. so the possible factors are 1, a, ab, ab², ab³, b, b², and b³</p>
<p>i thot s(root)3 was the long diagonal? Wasn s(root)2 the diagonal which is the diameter?</p>
<p>it depends on how sure you were on the ones you weren’t sure about. you could range anywhere from a 700 to a 790</p>
<p>gxing u r not talking about me are u?</p>
<p>no, my response was to strappleberry.</p>
<p>i might take it over in october sr yr, i just hope that taking it right after a chem SAT II wouldn’t do too much . plus, some schools do rolling admission so that’d be too late… </p>
<p>btw, thanks for the help, i think i’m gonna cancel.</p>
<p>Raw of 28 is about 660.</p>
<p>THAT was the prime number problem? That was so easy.</p>
<p>s<em>rt(3) IS the long diagonal – the answer IS (s</em>rt(3)) / 2</p>
<p>What was the answer to the question with the two polynomials with how many roots h(x) could have?</p>
<p>i think it was 2, 3, or 4. there’s an answer to in somewhere in this thread.</p>
<p>anybody know any more question?</p>
<p>what did u guys get for the question for the number of judges. Where two people got scores of 5.2 (I think) and 6. and judges give 1-10 integer scores, the least amount of judges?</p>
<p>It was 5.4, not 5.2. I put 5 judges.</p>
<p>yeah, it was 5. something, but I put 5 judges too. What about the firealarm one?</p>
<p>firealarm was the only one higher than both of them, that’s how it made sense conceptually, there’s a way to do the math but no need</p>
<p>The firealarm was the highest answer, .997 I think (it was easy if you looked at it as the “probabilty of a or b must be greater than the probability of only a alone or of b alone” the only answer higher than either of the probabilities was .997. I think I put six for the judge question because I was able to work 6 into being 5.4, but I think now I was wrong</p>
<p>what about the arithmetic sequence one? I kept trying to solve it but for some reason it wouldn’t work. don’t you do:</p>
<p>600=5(15-1)+a1 ??? Not too sure…</p>
<p>5 is correct because 3*5.4 = 16.2 which is not an interger –> means no judge can give a score of 0.2</p>
<p>5*5.4 = 27 which is an interger, and this sum is possible to many combination of five intergers.</p>
<p>what was the prime number question?</p>