<p>Also: cos (x-k) = sin (x), or something like that</p>
<p>The answer was k = pi/2</p>
<p>Be careful in your use of the word integral: it has some [very</a> important and specific meanings](<a href=“http://en.wikipedia.org/wiki/Integral_(disambiguation)]very”>Integral (disambiguation) - Wikipedia), and not really the meaning you intended.</p>
<p>/nitpick</p>
<p>for the jeans question:</p>
<p>what were the ANSWER CHOICES?</p>
<p>free candy for those who can remember!!!</p>
<p>:)</p>
<p>jeans question:</p>
<p>A)15%
B)30%
c)0% ??
d)25%
e)45%</p>
<p>
</p>
<p>The last two are wrong. I specifically remember that they were negative percentages.</p>
<p>so 25% was definitely not an answer choice?</p>
<p>
Definitely not.</p>
<p>it was like 60% loss, 30% loss, 0%, 30% gain, or 60%gain, for 60 im sure was one of the answer choices cause thats what i put</p>
<p>edit: so do u guys think this test was generally harder than the blue book and will have a slightly easier curve to work with?</p>
<p>the answer was 30% gain…i don’t remember the entire solution, just my answer…which i think is right…lol</p>
<p>yea, it’s 30%</p>
<p>Let me make some corrections and add a few more </p>
<p>8 divisors
6! for cars
4.8 cone
.997 probabilty
all sides for law of cosines
.93 for x
30% for jeans
s(root)3/2 for sphere
2sin(theta)
3,4 roots –> the question specific said that at least one different root
5 for judges
5 for sums
a^2 + 1
f(x-1) = shift 1 to right
7.78% for NYC
x+y = -1
I and II for -sinx and abs(sinx)
for the temperaure, it should be I and II –> choice (D)
(a^3)^2 = 123.1 a = 2.2
(A)none for the ingegral (73, 83) question
the first problem was like whats f(x-2)^2 or something, i think was 2
(2,-4,0) for distance
39.55 for bounceball
x greater or equal to 3
x > 3 (for another question, can’t remember)
(I)sinx and (II)|sinx|</p>
<p>the curve ques,asking a line and a curve…i thot the ques is asking wut is the range of x if the corresponding y value on the line is greater than that of the parabola</p>
<p>The curve question wanted to know the interval of x values for which the line was above the parabola. If I remember correctly, this went from 0 to 3 (perhaps higher), non-inclusive.</p>
<p>puddinggirl: f(x-1) = shift 1 to right</p>
<p>are you sure? cuz to me it should be one to the left. when you plug in 1 for x, f(1)=g(0)</p>
<p>the answer to the curve question was 0 to wherever the line crossed the curve…0 to 3 might be right</p>
<p>also, for the tanx sec^2x question, if tanx=b(a constant) shouldnt sec^2x be the derivative of tanx, which is 0???</p>
<p>f(x-1) is definately one to the right.</p>
<p>
</p>
<p>The graph absolutely shifts one unit to the right.</p>
<p>Consider f(x) versus f(x-1):</p>
<p>f(x):
f(0) = 0; thus (0,0)
f(1) = 1; thus (1,1)
f(2) = 2; thus (2,2)
f(3) = 3; thus (3,3)</p>
<p>f(x-1):
f(1) = 0; thus (1,0)
f(2) = 1; thus (2,1)
f(3) = 2; thus (3,2)
f(4) = 3; thus (4,3)</p>
<p>If you notice, in the second equation the x value is increased by one at each specific y value. Thus the equation shifts rightward one unit.</p>
<p>What were the prime number and cone problems? I don’t remember reading them AT ALL…crud</p>
<p>
</p>
<p>That question involves Pythagorean identities, not derivatives. There is no calculus on the Math IIC.</p>
<p>The identity in question is: sec^2(x) = tan^2(x) +1</p>
<p>We’re given tan(x) = a, and asked to find sec^2(x) in terms of a</p>
<p>Substitute the identity for sec^2(x), and the resulting expression is tan^2(x) +1. Since tan(x) = a, (tan(x))^2 = a^2.</p>
<p>Thus the simplified answer is a^2 +1.</p>