<p>it has an effect on admissions… it also depends on the rest of your stats/essays/recs…
i think i’m going to cancel, because i didn’t pace myself correctly… and ended at #38… should i?</p>
<p>Maybe. I do have a chance at 800. I will just pray. I took the Bio and got a 730. Then I took the chem and got a 750. I think that as long as you are in the range that is all that matters. When it gets that close they don’t really see the difference of 10 points.</p>
<p>A senior at my school got into MIT, I asked him and he got a 790 on his SAT IIC. He doesn’t really have anything special that would make him stand out.</p>
<p>If you ended at 38, you left 12 blank? Assuming you got maybe 1 or 2 wrong in the previous section, that’s about a 35 to 38 raw. Optimistically, you can get a 750. Realistically, you can probably get 710-740. Not that bad, but it depends on what college you want to go to.</p>
<p>Yeah. What were his SAT I scores. Was he a minority? Did he play music or sports?</p>
<p>My one suggestion for MIT would be to find an inventive, rigorous independent scientific thing to do. Whether it be science olympiad, doing original research, or participating in a major competition, that makes you stand out and (I believe) that’s what MIT really prefers.</p>
<p>No he wasn’t a minority and I don’t think he plays music, He runs Track and Cross-Country (he was on the team with me), he’s ok, few medals and tropheys I suppose.</p>
<p>Yeah. I am really good at math and science. I took Calc in 10 and BC in 11. I have a lot of unique science stuff like research but I am not so sure about my SAT I’s. I haven’t take the new ones and I took the old ones once and did really bad. I am going to take the new ones in October.</p>
<p>Yeah. I think I stand out. I just hope that I don’t get brushed away because of scores. I should be able to do better when I take them again. Who knows. People have amazing scores and still don’t get in. Now they only except 14%.</p>
<p>I will talk to you guys later. Good luck with college. Best wishes. E-mail me if you get a chance. Thanks</p>
<p>the last 7 problems… were hard. not all, but half of them were very hard.</p>
<p>for the UNIQUE ROOTS, i put 4. but i think its 2,3,4.</p>
<p>skipped ** 5** missed 2? is that -7 or -8??</p>
<p>I think I didnt miss any so far except I have 3 funnies (my way of saying not sure questions). So does that bring u donw to a 750? I REALLT WANT A 800</p>
<p>The correct answer to the distinct roots question was 4, 3, or 2.</p>
<p>Omitting five and getting two wrong is -7.5, which goes to -8.</p>
<p>If the curve is particularly generous, that’s a 800. If not, it’s a 780-90.</p>
<p>Three wrong and no omits is a perfect 800.</p>
<p>Can you remember what questions you’re unsure of?</p>
<p>how was that question 2,3, and 4 if all 4 roots are distinct? doesnt it have to be 4?</p>
<p>Umm the last question, the one about a cube inscribed in the sphere and like a one with the choices I II III.</p>
<p>The answer to question 50 was E, or 4.8.</p>
<p>The answer to the cube in sphere question was (s*rt(3))/2.</p>
<p>There were two questions I remember involving I, II, and III. The temperature question (involving a function with e in it) and the trig graph question. In both, I and II were correct and III was wrong.</p>
<p>my last question was about a cone.</p>
<p>pimpthatthang:</p>
<p>Abstract Proof:</p>
<p>h(x) can have 2 roots if f(x)=m(x-a)(x-b) and g(x)=n(x-a)(x-b); h(x)=mn(x-a)^2(x-b)^2 and you have two distinct roots.</p>
<p>h(x) can have 3 roots if f(x)=m(x-a)(x-b) and g(x)=n(x-a)(x-c); h(x)=mn(x-a)^2(x-b)(x-c)</p>
<p>h(x) can have 4 roots if f(x)=m(x-a)(x-b) and g(x)=n(x-c)(x-d); h(x)=mn(x-a)(x-b)(x-c)(x-d)</p>
<p>Concrete Proof:</p>
<p>h(x) with 2 roots:
f(x) = 2(x-1)(x+2) ; g(x) = 3(x-1)(x+2)
f(3) = 2(2)(5) = 20 ; g(3) = 3(2)(5) = 30
h(x) = 6<em>(x-1)^2</em>(x+2)^2 ; two zeros: 1 and -2</p>
<p>h(x) with 3 roots:
f(x) = 2(x-1)(x+2) ; g(x) = 3(x-1)(x+3)
f(3) = 2(2)(5) = 20 ; g(3) = 3(2)(6) = 36
h(x) = 6<em>(x-1)^2</em>(x+2)(x+3) ; three zeros: 1, -2, -3</p>
<p>h(x) with 4 roots:
f(x) = 2(x-1)(x+2) ; g(x) = 3(x-4)(x+3)
f(3) = 2(2)(5) = 20 ; g(3) = 3(-1)(6) = -18
h(x) = 6(x-1)(x+2)(x+3)(x-4) ; four zeros: 4, 1, -2, -3</p>
<p>Not all roots have to be distinct. I’m sorry if I mistakenly said that before.</p>
<p>
</p>
<p>What he meant was: the last question on the test, the question on the test involving a cube in a sphere, and the question involving I, II, III</p>