<p>hahah, Im not even close to an 800</p>
<p>Maybe a 700 if Im lucky. retake!!!</p>
<p>****Someone in a new thread brought up a new question that we haven’t discussed. sin(x)=.91 (apparently) and tan(x) was some negative number. I thought it asked for x, but the poster said it was asking for cos(x), which could be. So basically, just get x by doing arcsin(.91) then subtracting it from 180 because the tan is negative (sin positive means its in quadrants I or II, tan negative means its in quadrants II or IV). Then get the cos(x) normally if that’s what it asked for.</p>
<p>Anyone remember this, and agree or disagree?</p>
<p>That gives an answer of -.414 which is what I put!!! You better be right Bog!</p>
<p>I remember that question, don’t remember the answer though. It was a esay calculator question.</p>
<p>The other post asked a different question.</p>
<p>If you took the arcsin of .91 and the arctan of the other number I don’t remember, you got different results and different results for cos(x). Just taking the arcsin of .91 and plugging it in was a trap.</p>
<p>Well if Sin(x) is positive, the Tan(x) is negative, then the Cos(x) must be negative because if you divide a positive by a negative, the answer will be negative. So choose whichever value is negative.</p>
<p>Does anyone have the exact question?</p>
<p>I don’t exactly remember the tangent being negitive (but if Bog does, okay). If the tangent was negitive, the answer was -.414 and if it was positive, the answer is .414. You get this by using the sin(x)^2+cos(x)^2=1 identity, plugging in .91 for sin(x), and solving to get cos(x) equals plus or minus .414. I hope the answer is negitive, I had positive but changed it to negitive.</p>
<p>i believe the answer is -.414.</p>
<p>Everyone now agrees that it is negitive .414 because the tangent was negitive and the sine was positive, therefore it was in the 2nd quadrant and the cosine is negitive. I’m glad I got that one right. Was -.414 choice C and .414 D?</p>
<p>This one hasn’t been brought up. </p>
<p>Which of the following can be included in the domain of (e^x*ln(x-7))/(x-4)?</p>
<p>I. 4
II. 6
III. 8</p>
<p>Answer-III only.</p>
<p>** 1.85 for sqrt(2+sqrt(2)), 1st question. maybe it’s something else, but it was definitely something you can just plug into your calculator.
** 2.2 for (a^3)^2 equals 123.1
** 30% for the profit on the jeans
** 29.69 for the perimeter of the triangle (3<em>7sqrt(2))
–it’s actually 29.698 on my calculator, maybe the choice was 29.7?
*</em> 2sin(theta) for the unit circle thing, length of chord AB
** .997 for fire alarm probability
** x>=3
** 39.55 for bouncing ball (does anyone remember how many bounces it was?)
** “x=y or t=0” for under what conditions would xt=yt be true
** -x^2 + 2
** 1+a^2 for the tan(?)=sec^2(a) or whatever
** SHIFT TO THE RIGHT for g(x)=f(x-1)
** ALL THREE SIDES needed for finding the angle B
** 8 factors for the factorization where 3 prime factors are the same and 1 is different
** 5 is the first in the arithmetic sequence
** 5 judges needed to get 5.4 as a mean
** x>3 for |x-3|/(x-3)=1
** s<em>sqrt(3)/2 for the radius of the sphere with the inscribed cube
*</em> t>=3x for the logic problem where it said t<3x if 1<y<4, which it wasnt
** 6! for the permutations of 8 colors with 2 of them being set
** NONE for integral numbers on the line between (0,0) and (73,83)
** 7.78% increase for NYC after 25 years, with the .3% annual increase
** -.83, or -3/sqrt(13) for where you get the sin of theta where the point is (-2,-3)
** .93 for the length of the minor arc
** PI/2 for cos(x-k)=sin(x)
** Only I and II for temperature of cheese (starts at 75, approaches 55, but does NOT reach 50)
** Only I and II for which of the functions can fit the graph (-sin(x),|sin(x)|, but NOT cos(x))
** 2.6 for the greatest zero of the equation x^4-2x^3-8x^3+14x+7
** 2 3 or 4 for the number of distinct roots
– “f(x) and g(x) are different for at least one value of x” was basically the wording, not that the roots were distinct
** (2,-4,0) was the point double the distance from the origin in the other direction if the original point was (-1,2,0), just multiply all coordinates by -2
** 0<x<3 for what x values give a greater y value for the line than for the parabola
** (x-1)^2 + (y+2)^2 = 4 for which equation puts (1,2) outside the circle
** the graph where everything is positive for |f(x)| (it has two humps in the middle, i’m SURE you got it right)
** -1 for (2x-1)^2 + (2y+3)^2 = 0 and it asks for x + y
** 4.8 (E) for cone problem
** -.414 for sin(x)=.91
** III only for domain</p>
<p>Wow, 37!! Missed 7 so far. No omit. :(</p>
<p>I think the 8 and the 4 were switched. Also, 6 should be -6. It should read:</p>
<p>I. 8
II. -6
III. 4</p>
<p>But yes, only 8 is correct. You can’t have a negative natural log and you can’t divide by zero (ln -6 and X - 4)</p>
<p>I <em>think</em> it was 6.</p>
<p>I recall it being 4, 6, 8, though it may have been 8, 6, 4.</p>
<p>Anyways, yeah. It was 8. You should write the problem on the list, and the answer, 8. That way people instantly remember. III only for domain is vague, and doesn’t spur recollection.</p>
<p>I agree with Bog. I remember it being 6, and I am SURE that it was in order 4,6,8 because the answer was III only.</p>
<p>Scores in 6 days :eek: 
:mad: 
:rolleyes: :o</p>
<p>i think that’s what i put. i forget.</p>
<p>It wasn’t 6. 6 would actually work. It was -6. I think everybody agrees the answer was 8 only.</p>
<p>6 doesn’t work because then you would take the natural log of -1 which can’t be done. They put 6 in there to trick you (which is a perfect reason why it was 6 and not -6, 6 was a trick while -6 wouldn’t have been and that is the way ets writes the tests). And only 1 person thought -6, two thought 6.</p>
<p>Whatever. The 6 answer gave you a negative log. I do remember that. However, I think 8 might have been I instead of III. That I am slightly more sure about.</p>
<p>Oh well, I put 8 only whatever that was. haz, do you remember any more questions AT ALL? What do you think your going to get?</p>