<p>how was the cone 4.8? i put 3.0. what was the question again?</p>
<p>16.1M(1.3)^25 i believe</p>
<p>anyone remember the cone problem?</p>
<p>ok yeah, my bad 1.03^25=2.09 (1.09 increase) wasn’t even an answer, stupid me</p>
<p>yeah it said .3 and i did the formula 16.1 * (1.3)^25 and i couldnt get an answer</p>
<p>There’s a cone with radius 3 cm and height 6 cm. It is divided horizontally (parallel to the base was the wording) into two portions of equal volume. What is the height of the smaller cone?</p>
<p>does anyone remember his answer to the discount shirt problem? was it 30% bargain?</p>
<p>Cone problem (iirc):</p>
<p>Original cone:
r = 3
h = 6</p>
<p>Divide the cone with a plane parallel to the base (so you cut it flat and smooth) so that the two new sections are equal in volume.</p>
<p>What is the height of the smaller cone?</p>
<p>the volume and the height, as u go higher the radius gets smaller so the height of the first half has to be small, if it was 3 it would cut it in half…</p>
<p>Oh I Thought The Question Was Asking For Cylinder Instead Of Cone, Damn!</p>
<p>I think it has to be higher than 3 for the cone because it will have a smaller radius than the other part, but maybe I am wrong. It was 30% profit.</p>
<p>what was up with number 44? it said y = 5 and something like 1<y<3. why would y be less than 3 if it is equal to 5??? i left that one blank.
total i left 15 blank and maybe five others wrong…do u think i could get 670 or above.?</p>
<p>CONe problem: simply because the cone is wider at the bottom and thus the top would require more volume to set it equal, I said either a or b. I forget</p>
<p>on the nyc one it was .3% so wouldnt it be 16 * (1+.003)^ 25??</p>
<p>Kirbywamu posted a good solution to polynomial prob:</p>
<p>"the polynomial problem should be 2, 3, or 4.</p>
<p>h(x) can have 2 roots if f(x)=m(x-a)(x-b) and g(x)=n(x-a)(x-b); h(x)=mn(x-a)^2(x-b)^2 and you have two distinct roots.</p>
<p>h(x) can have 3 roots if f(x)=m(x-a)(x-b) and g(x)=n(x-a)(x-c); h(x)=mn(x-a)^2(x-b)(x-c)</p>
<p>h(x) can have 4 roots if f(x)=m(x-a)(x-b) and g(x)=n(x-c)(x-d); h(x)=mn(x-a)(x-b)(x-c)(x-d)"</p>
<p>what do you think the curve will be? 800=43 or higher/lower?</p>
<p>“what was up with number 44? it said y = 5 and something like 1<y<3. why would y be less than 3 if it is equal to 5???”</p>
<p>The point was to say that since the 3<y<4 part is wrong, the part before it is wrong as well. The question is asking you to see that since the part before it (x<3 or something like that) wasn’t true, the negation of it was.</p>
<p>i wanna say 45…it seemed alot easier than barron’s, which I know is expected but im sure a bunch of people aced this thing…</p>
<p>but iostream, for the polynomial problem, the first answer can’t work. the problem said that the 2 equations have to have at least 1 different point so f(x) cannot equal g(x) therefore i put 3 or 4 roots.</p>
<p>ooooooooooooooooooooo
i thought they meant .3 as in 30 percent … ugh im sooooo dumb i knew how to do it!!!</p>