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<p>The most encompassing answer would be just II… I took “intersecting” as having at least one solution on the x-axis.</p>
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<p>The most encompassing answer would be just II… I took “intersecting” as having at least one solution on the x-axis.</p>
<p>u guys are right…it wasn’t a roman numeral question</p>
<p>i put k<=0 i hope thats right!!!</p>
<p>Yeah, it was K<= 0 because the parabola would at least intersect the origin then as well making that the LEAST possible set of conditions where the parabola would touch the x-axis.</p>
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<p>Actually, the question was a little different. You had a circle with center O and a point B on the circle; you also had points C and D on the circle such that the chord created by CD was perpendicular to radius OB (Radius was given as 5 and CD is 8). You needed to find the sine of the angle created by OCD. Like this:</p>
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<p>You know OB is 5. OC and OD will be 5. Let the intersection of OB and CD be point E. Let OE = x and EB = (5-x); let CE = y and ED = 8-y. So you have the equations:</p>
<p>x^2 + (8-y)^2 = 5^2
x^2 + (y)^2 = 5^2</p>
<p>Subtract the two to get (8-y)^2-(y)^2 = 0. y=4. Thus, x=3.
CE = 4; OE = 3.</p>
<p>So sin(OCD) = OE / OC or 3/5 (answer was A).</p>
<p>EDIT: Actually I just realized you were talking about a completely different question… sorry about that. The work I showed was for another question that was still on the test though.</p>
<p>hey guys im taking the math IIc next month…from ur experience what do u think is the best prep book (pr, kaplan, barrons) and which one has the most realistic practice tests??
thanks</p>
<p>Princeton Review.</p>
<p>I believe there was some rounding with -4.85 as the answer, which might explain why you guys didn’t get perfect results by plugging it in.</p>
<p>I did use the calculator to solve that problem though, so I’m fairly sure -4.85 is the right answer.</p>
<p>how about the Q that was like z = 1 - i , whats z^2 on the graph… I said it was at (2,0), but I was running outta time</p>
<p>I think it was at 0, -2. 1-i squared is -2i.</p>
<p>No prep book is even needed, coz the test is too easy. It is easier than PR.
No kidding. I finished the test in 45 minutes, leaving me about 15 minutes to check the answer.
But I’m nervous now because if I get a really low score, like <750, I’m gonna kill myself.</p>
<p>most of the test wasn’t too bad…but from this thread i know i missed 2, and those are only the ones we discussed, so i don’t think i did too hot.</p>
<p>Agreed, hoganwan.</p>
<p>sigh~ people should stop discussing the test. The test IS OVER. Just let it go. You can’t change anything except letting youself down because you know you are wrong.</p>
<p>so I think I left 12 blank…and even i missed all of the ones i answered a still get about 670, when my goal was 650. So I think i’m somewhere around 720, which is good enough for me, ill retake anyway</p>
<p>Preparation book? I just used the free CollegeBoard booklet that my counselors gave me (it’s also available on-line) and the back cover of my calc textbook.</p>
<p>haha…</p>
<p>truth thats what I had at first but I think it would be -2(i^2) making it (2,0)</p>
<p>Hmm. All I did was put 1-i in the calculator and square it, so maybe I did it wrong…</p>
<p>I am astonished you’d need a calculator for that.</p>
<p>I’d do anything up to and including crapping on the test if it meant I’d get a good score, so using a calculator to square complex numbers isn’t that far up ; )…</p>