<p>Hm, I think i got 1-45 or something around there.
I automatically took out the 90’s because I plugged in sin(89) and cos(89) and cos was smaller, which doesn’t fit sine must be less than or equal to cosine,</p>
<p>No, it was 0<x<45 since sin(0)=0 and cos(0)=1 so until the pi/4(45deg) point where both sin and cos is equivalent, he values of sin are always smaller than the values of cosine. This question was almost too easy so I hope I didn’t read it wrong.:(</p>
<p>I’m trying to figure out if that equation problem had 2 intersections or none but I can’t remember the equation!!! Someone here must have a photographic memory right?</p>
<p>for the intersection thing i stupidly guessed 5. 
:(</p>
<p>great, i shouldn’t have relied on the calculator</p>
<p>now i got 2 wrong at least >:</p>
<p>xy^5-2x=SOMETHING</p>
<p>what is the something??</p>
<p>xy^5-2x is just y=2^(1/5) which is just a straight line paralle to the x axis</p>
<p>the other graph i remember being a parabola going down with vertex at (0,0)</p>
<p>oh wow, two wrong. i got at least 10 wrong, no kidding.</p>
<p>well this is my second time taking it and i’ve prepared quite a bit for it</p>
<p>from this thread, i see that i got at least 4 wrong. that’s just based on the ones discussed here :(</p>
<p>Heh, how’s the curve like?</p>
<p>I think I got at least 10 wrong too, ugh…is it possible to get 10 wrong and still be able to break 750?</p>
<p>For the F(A/4) i reduced it to sq. root(.5) cuz f(a)=0 so when you solve it you get f(a/4)=0 i think… then it was just sq root((1+0)/2)</p>
<p>yes(10 char)</p>
<p>I hope I got over 700…I think my answers agreed with nearly everything in this topic…</p>
<p>I felt like the test was mostly testing my knowledge of how to use my calculator.</p>
<p>I think I skipped two, maybe three. I know I skipped the polar coordinates one, 'cause we’re not doing that till next semester.</p>
<p>I was amazed that there was a question that involved the z-axis as well. I figured being in calc BC it would all be stuff that I’ve covered.</p>
<p>xy^5-2x=something. For that problem, it asks the intersect with x-axis. So you make y=0, and solve for x.</p>
<p>or you can solve for y and just graph it</p>
<p>arkman- wrong</p>
<p>it’s RAD(1+0.7071/2)</p>
<p>HEY did you guys do the graph problems?? with the w/h ratios for the height, weight, for students?? there were two questions for that graph… i forgot what i put for the 1st one, but i skipped the 2nd one</p>
<p>I think the first one was .248 (median of w/h ratio). And the second one was about averaging the w/h ratio on the graph and finding what W would be if H = 48 or something.</p>
<p>I just realized that I solved the w/h one backwards. I’m pretty sure I solved for h if w was 48. Maybe possibly. Maybe not.</p>
<p>will we get our scores back before the deadline for signing up for December tests?</p>
<p>Well, I remember the answer being being a three digit number, maybe like 273? I’m not sure…and no, the December deadline is conveniently the day RIGHT before we get November scores (assuming they come out 11/2).</p>