<p>the median question was find 15 pos numbers whose median was the same as the range, so the numbers could have been 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 in set a</p>
<p>s
But in set b, the numbers were either multiplied by 2 or by 4, i forgot,</p>
<p>but either way, lets say 14 (the median of set a) is multiplied by 4, it is 56, and if 21 is multiplied by 4, it is 84, and 84-56=28, so the range is 28, which is half of 56, so the answer should be m=2r</p>
<p>@jlee - your reasoning is incorrect. It never said it was increasing in order. It could have been 2,2,2,2,2,2,2,2,2,2,2,2,2,2,4</p>
<p>Still no consensus on this:
ABCD number line math question
I, II, III</p>
<p>What was it?</p>
<p>@wilt: do you remember the exact question?</p>
<p>Houston: I put all 3</p>
<p>and for the ones with the x squared multiple of 8, did you guys get 33?</p>
<h2>@ces0797</h2>
<p>looooking at her calculations…
m=2r seems plausbile …</p>
<p>@ces0797 yep i got all three</p>
<p>range is equal to largest - smallest. 84 - 28 is 56. it’s m=r</p>
<p>I hope section 3 math was experimental…</p>
<p>Wasn’t the question asking about median and mode? I do not remember it saying range…</p>
<p>The ID question on the river serenely, I got no error? How is it before finally?</p>
<p>@jlee the range if you multiplied the set by 4 would be 84-28=56, its not 28, you didnt subtract the highest from the lowest, therefore m=r</p>
<p>Abcd was all 3, pythagorian not experimental</p>
<p>@houstonrep</p>
<p>I put I, II, and III for the abcd question</p>
<p>was abcd the experimental?</p>
<p>What was #13 on sec 10? I got the really short answer</p>
<p>was abcd the experimental section for math though? someone please answer this question…</p>
<p>what the short answer e?</p>
<p>Abcd WAS NOT experimental. Had 4 CR and that was still there.</p>
<p>My bad @samuelkim I put 12 for the perimeter of that triangle (so obvious) since it’s a 3, 4, 5. </p>
<p>You guys are over-thinking the m and r problem. Given the requirement that a set of fifteen numbers must have the median equivalent to the range, make up values. As I posted earlier, choose 10 to be your m and r. You can have 20 as the greatest number and you don’t have to have more than one. Convenientally, there was nothing saying that the integers had to be distinct. Anyway, have one 20 and fourteen 10s. Obviously the m and r are equal (10 is both). Quadruple that and m and r are still equal. 80-40=40 and 40 is the median. There ya go</p>
<p>@yankees. I put interference, E</p>