<p>by the way spidey,in Bangladesh,this kind of questions are very common when you take exams to prove your ability to study in top engineering universities…i am a 1st year student of civil engineering in BANGLADESH UNIVERSITY OF ENGINEERING & TECHNOLOGY.lol,i remember those dayz when i had to do that kind of math…</p>
<p>i like your blog@spidey…</p>
<p>hehe @gluttony - thanks</p>
<p>@diamondbacker - I was only referring to the tough level of questions. If you ask me, that exam admission system sucks since only the exam decides your fate! 
Which is why I’m here lol</p>
<p>@gluttony, what will you do after taking SAT? 
Transfer? Since you’re already in college.</p>
<p>do reply ,
And if it helps, SAT 1 math questions are not really arithmetic, they’re simple and more logic based, where math involved is mostly just calculation.</p>
<p>N0,i d0nt intend to transfer.i shall apply to usa c0lleges to start fresh,my preferred subject is pharmacy. .
U know how simplest l0gic que can scare da daylight out of any1.i m here to practise and ask 4 help when needed.its a great site,i g0t a l0t 4m members</p>
<p>Yup, and it’ll help to buy a SAT book by Kaplan or Barron. The first time I gave SAT, I had no practice and no idea of the format of questions, I didn’t even know the sections are timed by themselves and you can’t shift or arrange your time management overall. I just got 1960! 
lol … I’ve taken tests from Kaplan and Barron now and scored around 2300 in them. My SAT is in october … Generally speaking, if you go through those questions once, you’ll find them easy pretty soon, the essay is what hits you hard (I still hate it )</p>
<p>spidey, it’s wrong
remember for inequalities, it can be negative so it can also switch signs
this info applies for sat 1 too.</p>
<p>good, got it YEp.</p>
<p>The full proper method will be to take various positions of x… between the critical points, and then solve the equations and take the intersection of the domains obtained to get the final domain.</p>
<p>that was a minor mistake,but im sure it’ll hurt if its on sat 1 lol.
thats why i usually avoid those inequalities with dividing / mult
jump straight ,plug in # or my calc XD</p>
<p>just if your curious
the proper way to solve the inequality is the following:</p>
<p>(x+4)/(x+1)>(x+2)/(x+3)
(x+4)/(x+1)-(x+2)/(x+3)>0
[(x+4)(x+3)-(x+2)(x+1)]/(x+1)(x+3)>0
(x^2+7x+12-x^2-3x-2)/(x+1)(x+3)>0
(4x+10)/(x+1)(x+3)>0
now here’s the trick, multiply by the square of (x+1)(x+3) on both sides, then it will always be positive
(4x+10)(x+1)(x+3)>0
the 0’s are -2.5, -1, -3
and since the function is a polynomial with 3rd degree and positive leading coefficient, the graph will have a negative value in the left direction and a positive value in the right direction
thus, by sketching the graph, the answer is
(-3,-2.5) and (-1,positive infinity)</p>
<p>Good. yes.</p>
<p>OK, I can’t resist. This shouldn’t be too hard for you guys.</p>
<p>x*w + y/3 = 7</p>
<p>The line above is perpendicular to the line: 12y - 2x = 11.</p>
<p>What is w?</p>
<p>W = 2</p>
<p>10char</p>
<p>do explain,diamondbacker</p>
<p>The line is perpendicular to 12y - 2x = 11.
The slope of the line 12y-2x = 11 is 1/6:
12y - 2x = 11
12y = 2x + 11
y = (1/6)x + 11/12</p>
<p>Therefore, the slope of the line wx + y/3 = 7 is -6, the opposite reciprocal of 1/6.
Solve for y to put this equation in slope-intercept form:
wx + y/3 = 7
3wx + y = 7
y = -3wx + 7
In this equation, -3w is the slope, which should be -6.
-3w = -6
w = 2</p>
<p>x<em>w + y/3 = 7
The line above is perpendicular to the line: 12y - 2x = 11.
12y - 2x = 11
y = 11/12 + x/6
slope = 1/6
Therefore slope of line perpendicular to it will be -6.
x</em>w + y/3 = 7
y/3 = 7 - wx
y = 21 - 3wx
therefore, -3w = -6
w = 2</p>
<p>Lol,that x*w got me confused.i mistakenly took tht as x^w.he could have written simply wx or xw</p>
<p>^But then it wouldn’t have been a line. Or, you could immediately say: w=1.
OK, here’s a fun one (an “A” problem?):</p>
<p><a href=“http://www.erikthered.com/tutor/sat-geom-question-1.png[/url]”>http://www.erikthered.com/tutor/sat-geom-question-1.png</a></p>
<p>^</p>
<p>180 = (180-x) + (180-y) + (360-z)
180 = 720 - x - y - z
-540 = - x - y - z
540 = x + y + z</p>
![http://www.erikthered.com/tutor/sat-geom-question-1.png[/url]](http://www.erikthered.com/tutor/sat-geom-question-1.png%5B/url%5D){kind=link}
