<p>D’yer Maker STILL winning? Lol</p>
<p>Obsession…?</p>
<p>Who? Me?/<em>hfjeshjkd</em>/</p>
<p>WIN.</p>
<p>Next up: 751 757 761 769 773 787 797</p>
<p>Note that the time and the poster number match. Very Zen.</p>
<p>If a=b and b=c, and c is a prime number, prove that the number green is divisible by blue.</p>
<p>Hold on one second. No flies on me. Is it also a given that green and blue are positive integers?</p>
<p>Ok, I will give you a hint. Green is defined as the duration of 9,192,631,770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the caesium-133 atom. This definition refers to a caesium atom at rest at a temperature of 0 K (absolute zero). The ground state is defined at zero magnetic field. </p>
<p>I thought you guys could figure it out without that, but now it should be really easy.</p>
<p>Simple. Only if the variable yellow is present. Otherwise, green is only divisible by D’yer Maker.</p>
<p>Not quite. It’s a bit more complicated than that.</p>
<p>Here is my explanation:</p>
<p>In many systems, two or more energy eigenstates have the same energy. A simple example of this is a free particle, whose energy eigenstates have wavefunctions that are propagating plane waves. The energy of each of these plane waves is inversely proportional to the square of its wavelength. A wave propagating in the x direction is a different state from one propagating in the y direction, but if they have the same wavelength, then their energies will be the same. When this happens, the states are said to be degenerate.</p>
<p>(By the way, the solution could be much more complex, but for simplicity sake we can assume that the variables are discrete, and that they are orthonormal. This way, I only have to write a few paragraphs of explanation instead of a textbook.)</p>
<p>Now, in the mathematical formulation of quantum mechanics, a physical system is associated with a complex Hilbert space such that each instantaneous state of the system is described by a ray (a one-dimensional subspace) in that space. The elements of a Hilbert space are by definition normalizable and it is convenient, although not necessary, to represent a state by an element of the ray which is normalized to unity. </p>
<p>From this information, it is clear that the number green is divisible by blue because of a similar cancellation of phase factors in bra and ket, where all average (expectation) values of time-independent observables (physical quantities) computed from \psi(t), are time-independent.</p>
<p>My eyes are glazing over, but I did notice this much: you wrote the word “bra” – and it wasn’t censored.</p>
<p>Dude, it’s Bra-Ket notation. That’s why it wasn’t censored.</p>
<p>bra
Did I inadvertently win? It’s 751. </p>
<p>Someone will probably post delete and steal my glory. 
I was never vindictive or anything, even. Just give me this one.</p>
<p>Eh…some doo doo head might delete their post…</p>
<p>753…:)</p>
<p>Ok, I have another one.</p>
<p>If Jimmy has 20 chickens, how long will it take him to make a nail bomb?</p>
<p>5 hours… :D</p>
<p>Right! Ok, I have another. </p>
<p>Using the transitive property, calculate the probability of a waffle-shingle imploding into a quasar.</p>
<p>Ha! 757!!! I Win!!!</p>
<p>I’m twice a prime number, which means I am three times a winner. Which makes me 4 times a winner, hence I lose.</p>
<p>761 769 773 787 797</p>
<p>Wazzapnin’. 
</p>