<p>Yes sirrrr</p>
<p>Wait… the 1997 question with the constant rate of change was 9.6?</p>
<p>@PencilxBoxes
Yes.
1995 was 9.8, 1996 was 9.7, 1997 was 9.6, and 1998 was 9.5
why was this problem so difficult for everyone? just curious</p>
<p>@Bob agreed…that problem was simple. You just look at the year and count down and assign each year n+.1 or -.1 can’t remember which way the rate of change went</p>
<p>I remember it says if t is 15% of p and t is r% of 20, how would you rank t,p, and r from least to greatest? if you substitute 1000 for p and 150 for t, it would be t<p<r. But If you substitute 100 for p and 15 for t, it would be t<r<p. So doesn’t it have two answers?</p>
<p>Didn’t it say r is what percent of t? not what percent of t is r?</p>
<p>so it would be t>p>r?</p>
<p>@LDerondo
A question will NEVER have two answers no matter what. Each question is thoroughly examined for possible errors and/or misleading text.
The question you have written is probably not identical to the one on the test.</p>
<p>Not sure, but according to the thread the answer is t<r<p. Anyone else remember this question, maybe I did read it wrong?</p>
<p>Like I’m not sure but I looked over for that question for a good minute and was sure I did it right. re-read like 3 times lol</p>
<p>The question was: T is 15% of P.
T is R% of 20.</p>
<p>You sure it wasn’t R is T% of 20?</p>
<p>@defianced,
If you’re right there could technically be two answers like I just explained. Im just hoping for more confirmations… maybe SAT finally made a mistake?</p>
<p>@LDerondo
SAT would never make a mistake like that. I found that the problem worked for multiple scenarios during the test. The test makers can make mistakes, but not as simple as these.</p>
<p>do you guys think that the p>r>t problem and the french and math students problem were in the experimental section?</p>
<p>@Giantsblue
Neither of those were in the experimental section. I had experimental CR, but I had both of those math questions.</p>
<p>@Lderondo</p>
<p>your “r” in first case is 750. your “p” as you stated is 1000. 750 < 1000, not 750 > 1000. therefore t<r<p (which holds true in all cases).</p>
<p>@iBelieveSo,
Dang it! you’re right</p>
<p>The question also could have been solved algebraicly</p>
<p>t=0.15p
t=0.2r
therefore</p>
<p>0.2r=0.15p
r=0.75p</p>
<p>therefore
p>r>t</p>
<p>was it A for the p,r,t question?</p>
<p>no it was e</p>