<p>^ You get 3/(n+1) because (n+1)! = n! * n+1</p>
<p>3 over n+1 approaches 0 as n approaches infinity, therefore it converges.</p>
<p>^ You get 3/(n+1) because (n+1)! = n! * n+1</p>
<p>3 over n+1 approaches 0 as n approaches infinity, therefore it converges.</p>
<p>Ahh I see. Thanks.</p>
<p>
</p>
<p>Yeah I realized this right after I did this the first time…now it looks like I’m just a sneaky person who edited it after seeing yours :x</p>
<p>lol i applied differentials at first and got 9. not sure why that doesnt work meh</p>
<p>Do we need to know Newton’s method for the exam? It’s something I never bothered learning…</p>
<p>^ I don’t think so.</p>
<p>hey guys, when you write the limits of integrals that has like 3 decimal places, do you have to substitute it for letters like P and Q?</p>
<p>on the FRQ, they do that alot, is placing 3 decimal place limits against the rules?</p>
<p>Hmm thanks for the swift reply ![]()
I decided I’d just go ahead and learn it though and I think I got it down :P</p>
<p>This is going to be a really stupid question, but if the point of inflection is when the 2nd deriv is zero, what’s it called when the first deriv is zero?</p>
<p>^ A critical number.</p>
<p>Is there any general rule to rounding on the FRQ?</p>
<p>Just saying, Newton’s method is not on the test.</p>
<p>so
1st derivative equals zero = critical number = when the graph of f(x) has a relative* max/min
2nd derivative equals zero = point of inflection = when the graph of f(x) changes concavity</p>
<p>correct? :/</p>
<p>Isn’t it just to round to at least 3 decimal places?</p>
<p>-
so
1st derivative equals zero = critical number = when the graph of f(x) has a max/min
2nd derivative equals zero = point of inflection = when the graph of f(x) changes concavity</p>
<p>correct?
</p>
<p>^
1st/2nd derivative can also be undefined for critical numbers & inflection points. And graphs may not always have a max/min at those values so just make sure to check.</p>
<p>^^And then there are umpteen tests to do to check to see what kind of stuff it does. @pbbuff</p>
<p>either rounding to 3 decimal places or truncating everything after the 3rd decimal place works =)</p>
<p>Truncating after 3rd decimal place? </p>
<p>E.g.
.3456 => .346 (rounded)
.3456 => .345 (truncated)</p>
<p>alright, thanks for the confirmation. i’m REALLY hating series right now, and also i have no idea how to justify any of my answers for the FRQ’s really…</p>
<p>Swag: my calc teacher always told us to round and never truncate</p>
<p>It doesn’t matter. Either rounding or truncating is correct.</p>
<p>Good night! I’m going to ■■■■■ these forums a little more and then hit the sack.</p>
<p>Everyone get PUMPED for a 3 hr 15 min exam!</p>
<p>WooT!</p>