<p>That answer was (0,-c). All you had to do was turn your test booklet 90 degrees.</p>
<p>thought so, thanks</p>
<p>umm can anyone explain to me the a(b^2)(c^4) > 0 problem, and why the answer is a(c^2) > 0 and not abc> 0 ? (i rushed through it 
)</p>
<p>since B and C are being raised to an even power, it doesn’t matter if they are negative or not. A is the only one that has to be positive for the inequality to be true. In that case, abc>0 would not work because b or c can be negative while a is positive, thus making the inequality false. For a(c^2), since c is being squared, it can be negative or positive so a must be positive for a(c^2)>0</p>
<p>(i think thats the correct explanation)</p>
<p>Well it’s not abc>0 because a=2 b=3 c=-2 =-12 which is less than 0, but for the original equation it equals 288 which is greater than 0. a must be positive because it is not being squared. If you plug in -3 for a and 2 for c (1 for b) than it results in -12. For the original equation, the output is -48, therefore a(c^2) MUST be greater than 0 for the original equation to be greater than 0 (which is stated in the problem).</p>
<p>i get it (blonde moment)…man it was the last question, i should have thot a lil more
Thank you very much tho</p>
<p>What do you all think the curve for math will be?</p>
<p>hey guys…just took the test today</p>
<p>couple of questions on the math…first off for the prize one where the teacher bought $90 worth of prizes, what was the answer?</p>
<p>I had to guess for like the last 8 questions and just put D in each time, did u guys get many D’s for the last one?</p>
<p>for the $90 prize one, the answer was 800</p>
<p>how do u get that?</p>
<p>system of equations</p>
<p>x+y = 1000</p>
<p>.05x + something*y = 90</p>
<p>solve for x</p>
<p>it was .25y</p>
<p>what were the questions to the answers “25 putunias” and “18x-17”</p>
<p>what was the answer for the one on law of sines?</p>
<p>i’m with clunster. what were the questions to those answers? I do not recognize the answers but if i see the questions i would be able to</p>
<p>and does anyone remember any questions/answers from the last reading section. it was the hardest of the reading sections and I think if we went over it, a lot of people would feel relieved(me)</p>
<p>isn’t it abc>0. Think about it the inequality would not be correct if either abc were 0 because 0 raised to any power is 0 and if a b or c were to be 0–the answer to it would be 0 therefore the problem wouldn’t be greater than 0. So would the answer HAVE to be abc>0??</p>
<p>no, if a and c are both negative, it would make it positive, but if a is negative, the inequality is not true. However if ac^2 is greater than zero, it means that a is positive, which makes the inequality true</p>
<p>I also put 0. I thought that 0 was the only way the equation would not work :O</p>
<p>Did anyone have lots of time after their Math portion? I thought it was actually pretty easy… Somehow, I had around 15 mins. left… Anyone else think it was easy?</p>