<p>I am a 9th grader who took collegeboard’s practice new sat and did decently. I got about an 800 writing (1 wrong), 730 verbal (3-4 wrong), 650 math (8 wrong). Now, I am very happy with my writing and verbal, and believe I can get the same scores consistently (I took an SAT last year 650 verbal, 550 math, though my verbal has improved considerably, both in comprehension and in not over analyzing passages). Though I don’t think my math is a 650, probably somewhere from a 550-650. Nonetheless, I’d like to take the New sat at the end of next year. When, and how, should I start preparing,(mostly if not all for math, my writing should be 750-800 and my verbal a 750), assuming I want a 730-750 in math? Many of my mistakes are careless, though I get lost in some geometry and Algebra 2 mc’s. Please forgive me for my drastic overuse of parentheses.</p>
<p>On a side note, can anyone tell me how the answer to this q is 600 (700 highest choice, rephrasedsed) How many numbers between 0 and 1001 (not including) are divisible by 5 or 2, or both. This was the last question, but it seems simple. 1000/5 + 1000/2. Either I made a mistake or college board did, because no number is divisible by 5 and 2.</p>
<p>more than anything you should settle down…only being in ninth grade and all. you have a while to go, time will mend those stupid mistakes that you make. But as for right now…you don’t need to worry, you’re only just beginning high school.</p>
<p>10,20,30,40,50,60…those are all divisible by 5 and 2, you can’t count those twice. Then you go on…count how many numbers are divisible by two that five doesn’t go into…2,4,6,8,12…and then only 5 5,15,25,35…</p>
<p>The easiest way: count how many of these numbers are within 1 and 10 (including). You will find 6 such numbers which are 2, 4, 5, 6, 8, 10. Since there are 100 10s between 0 and 1001 (and since whether or not a number is divisible by 2, 5, and 10 is only dependant on its last digit), then there are 6*100 numbers which are divisible by 2, 5 or both. </p>
<p>Or maybe, you can do what doesnotexist says. Count how many numbers within that range that are divisible by 2, then by 5. Add the result (1000/2 + 1000/5 = 700). Then count how many numbers that are divisible by both ([1000/5]/2=100). These 100 numbers are the numbers that you count twice. To find the answer, simply subtract 100 from 700, and you get 600.</p>