an abstruse math que that can make you suffer

<p>it’s really an easy que as i see it,but hey,its truly a tricky one proving collegeboard doesn’t want you to get a 800 in math with ease.
it’s from a BB model question: (test 3,part 2,que 17)</p>

<p>may the sat writers die a painful death----dont forget to try que 15,17,20 in section 2 of test 3 in BB.its a must if you want a 800 in math</p>

<p>please get the book right now and try out this freaking que.anyone having problems with the que can read the following as i explain the answer:
question
in the xy-palne,line l passes through the origin and is perpendicular to the line 4x+y=k,where k is a constant.if the two lines intersect at the point (t,t+1),what is the value of t?
a)-4/3
b)-5/4
c)3/4
d)5/4
e)4/3
</p>

<p>answer is B</p>

<p>solution
this stupid ******* question is just a tricky one.it says line l goes through origin and is perpendicular to line 4x+y=k,where k is an constant. <a href=“actually%20k%20is%20put%20here%20only%20to%20confuse%20you,there%20is%20no%20need%20to%20emphasize%20on%20it”>B</a>.if you know how to construct an equation of a straight line then make the equation with these 2 given clue:1)l goes through origin,2)is perpendicular to line 4x+y=k,where k is an constant.<a href=“you%20must%20know%20how%20to%20construct%20the%20equation%20of%20a%20line%20which%20is%20perpendicular%20on%20another%20line”>B</a>
now after constructing you will get the equation of line l : x-4y=0,
as you can see, the point (t,t+1) is on the line l,so put this value in the equation and you will get : t-4(t+1)=0,from this equation find out the value of t…now u get that t=-4/3…so you see,this isn’t hard but tricky one which can hamper you getting 800</p>

<p>ps-also try out que 15 and 20 of this section,it’s also a tricky one (test 3,section 2)</p>

<p>I’ll definitely look at those. I know I did them a long time ago, but I’ve forgotten them. </p>

<p>I had a tricky one the other day. How many positive integers under 1,000 are “triple-multiples,” where a “triple-multiple” is an integer that is the product of three consecutive multiples? </p>

<p>I didn’t see the pattern until I took the really long route (starting a 1x2x3 and going until you go over 1,000).</p>

<p>The easy way to do it is to think of what 1,000 really is - it’s 10^3 right? or 10x10x10. So, the HIGHEST “triple-multiple” you can get is 9x10x11 = 990.</p>

<p>Therefore, you can immediately know that there are 9 triple multiples under 1,000: the first starts as 1x2x3, then 2x3x4, etc all the way up until 9x10x11.</p>

<p>I dont see what was so tricky about 15 or 20. I got both of them in about 30 secs each.
For 17, I would plug in every answer choice. I dont really get the proper way to do it.</p>

<p>thanks to ** lolcats4**,it’s a question of great significance which underscores on your reasoning,definitely a tough one if you never saw a que like this before…lolcats4,please give us more questions that u think to be tricky</p>

<p>thats why i didn’t think of explaining those questions,coz they are easy to get,but also it’s easy to mistakenly emphasize the similar size of the triangles in que 15 and some people might forget to divide 15 by 12 to get the remainder 3 in que 17</p>

<p>Gluttony, I agree with you. That slope question was the trickiest question I Have ever done in SAT math. I have never done a problem like that, not even close. It was the only problem I omitted in that section. The remainder one, 15 divided by K with a remainder of 3. And how many values of k will this work?</p>

<p>This one was simple as long as you do it methodically and systemically; test all values between 3 and 12 (including 12). …I thought this was an incredibly simple problem…although my disinclinations are for slope problems. Ugh. My mind gets sluggish when it comes to these problems, I knew it had something to do with PLUGGING IN T, but I tried to solve for K first and that threw me off track. I condemn whoever made that problem.</p>

<p>^ thank you jextelox,i included that coz 1 of my friends answered it wrong (he is a moron.anyway)</p>

<p>Here is another fun one. It’s not so much hard as it is time-consuming, which makes it difficult as the last question of a section. </p>

<p>On a square gameboard that is divided into n rows of n squares each, k of these squares lie along the boundary of the gameboard. Which of the following is a possible value for k? </p>

<p>(a) 10
(b) 25
(c) 34
(d) 42
(e) 52</p>

<p>^
Answer is e.</p>

<p>yeah,answer is E…it took me 1 minute 9 secods :open_mouth: i m not joking,it’s really time consuming…it usually takes me 20 to 40 seconds to solve a que</p>

<p>i would like to know how lolcat4 & kysuke solved this que…here is my method:
question:On a square gameboard that is divided into n rows of n squares each, k of these squares lie along the boundary of the gameboard. Which of the following is a possible value for k? </p>

<p>(a) 10
(b) 25
(c) 34
(d) 42
(e) 52
answer: E</p>

<p>solution:
its a bit tricky to understand that the gameboard is divided into n^2 numbers of little squares (like a sudoku game,which is divided into 81 squares,there r 9 rows where each rows contains 9 squares)…so lets come to the point…lets say that there are x sqares on one side of the square gameboard.so 1 adjacent side of will have x-2 squares as the opposite side of the afore mentioned side will take another squre…so the total squares that lie along the boundary will be 2x+2(x-2) or, [B4x-4**…now when you put 4x-4=52,u get a integer value of x,but if u put anyother choice other than 52,u wont get an integer value for x.so **E ** is the answer</p>

<p>All you do is n^2 - (n-2)^2, which = 2n^2 - 4n + 4. Enter this in a calculator, and find out which y value gives you an integer answer for n.</p>

<p>^ i think this will explain what i meant by “lets say that there are x sqares on one side of the square gameboard.so 1 adjacent side of will have x-2 squares as the opposite side of the afore mentioned side will take another squre”</p>

<p>imagine a 5 into 5 square…now as u see,the uppermost and the lowermost row each has 5 squares and the rightmost and the leftmost coloumn each has 3 squares left to be counted as the other squares are part of the uppermost and lowermost side square count. 5-2=3…thats why i wrote down x and x-2…</p>

<p>so the total will be 2x+2(x-2) squares</p>

<p>wow amciw,yours too is also a great method.i hadn’t think about.yours is good too,but mine doesnt need any quadretic equation solving…but definitely…yours is real great</p>

<p>There is a REALLY fast way to solve my question:</p>

<p>You need a multiple of 4, minus 4 for the 4 corners. </p>

<p>If you want to be even faster, you know all you need is a multiple of four, haha </p>

<p>52 is the only choice that works. </p>

<p>Don’t bother with a calculator or anything like that - my method takes less than 10 seconds</p>

<p>^ i too don’t want to bother about calculator.like lolcats4 i too understood from my equation that the answer choice which is a multiple of 4 will be the answer…but i understood only after spending a long time (1 min 9 sec) to solve the que :frowning: need more practice in both math and english…i suck in CR</p>

<p>The border squares are 4 for the corners and 4(n-2). Add it up and you get 4n-4 so you’re just looking for a multiple of 4. Took me less than 10 seconds.</p>