AP Chem lab-related question...please help!!!

<p>For our final project in AP Chem, we're asked to devise two or more methods to determine the amount of an individual substance within a mixture. Half our class is entirely stumped, and the other half of the class is keeping mum about their answers. Typical chemists!!</p>

<p>The challenge is to determine the percentage by mass of two individual solids within a mixture. We'll be given a powder of NaCl and NaHCO3. We can basically use any materials in the lab that we'd like to complete the lab, but we're graded on our accuracy. We have to be within 4% error, I think!</p>

<p>Essentially, we devise two procedures to determine the composition of the mixture. The additional materials that everyone is provided is 1 M HCl, 1M H2SO4, balances and Bunsen burners. Other students have been using tubs of water, titration burets, ice and boiling water, and pH paper.</p>

<p>Do any AP Chemists out there have any suggestions? Our class is dying for answers!!!!!</p>

<p>There's a sticky on top that says "IMPORTANT: NO homework help posts are allowed on CC "</p>

<p>Sorry, we can't really help you. I suggest thinking about it carefully instead of waiting on someone else to do it for you. Maybe the answer will come in due time.</p>

<p>hmm....it doesn't rlly look that big of a deal....well, i was abt to help u but as the above poster reminded, I'd rather compile w/ the policy.</p>

<p>I guess I didn't notice the guideline. Thanks for telling me, though.</p>

<p>And rest assured about the hard work! You don't have to worry that I'll put in the effort required by the project. thanks for the replies</p>

<p>some hints: AgCl, K(suba) for carbonic acid and bicarbonate ion, common ion effect</p>

<p>yahoo answers ;)</p>

<p>yahoo answers helped me multiple times for chem this year :D</p>

<p>Do a titration...
Just add a couple drops of an indicator in and go to town.
Then you know the amount of need to neutralize the substance.
You can then do an equilibrium expression and solve from there. Just right the net reaction too and you can see what the ratio between the two compounds is.</p>

<p>Sorry if im completely off...but we did a very similar lab in class.</p>