At what point on y=(1/2)x^2 is the tangent line parallel to the line 2x-4y=3

<p>At what point on y=(1/2)x^2 is the tangent line parallel to the line 2x-4y=3?</p>

<p>This is an easy question but i get my answer wrong,the right answer is (1/2,1/8),how to do this?</p>

<p>My answer is (1,1/2).</p>

<p>y=1/2(x)^2
y’=x
The slope of the line is 1/2, so the derivative of the function is half when x=1/2. Plugging in 1/2 into the original function gives y=1/8, so the answer is (1/2,1/8).</p>

<p>^gotcha,thanks!</p>