<p>At what temperature will the Fahrenheit and Centigrate scales yield the same numerical value?</p>
<p>LOL that's just C = (9/5)C + 32 so -4/5C = 32 so C = -40 degrees. If you don't believe me then just plug it back into C = 5/9(F-32) using -40 as the temperature for F.</p>
<p>-40 </p>
<p>(10 char.)</p>
<p>oh duh thanks.</p>
<p>are you kidding me? That was a hw question? The only thing I have to say to your teacher is....WHY?</p>
<p>another hw question ihave, the one i asked was the firsat one lol. here's a harder one. </p>
<p>a horizontal steel I-beam of cross sectional area 0.031 Msquared is rididly connected to two vertical steel girders. If the beam was installed when the temperature was thirty degrees celcius, what stress is developed in the beam when the temperature drops to -30 degrees celcius. Is the ultimate strenght of the steel exceeded? What stress is developed if the beam is concrete and has a cross sectional area of 0.13 meters squared? Will it fracture?</p>
<p>The Fahrenheit/Celcius question was actually a $250,000 question on "Who Wants to Be a Millionaire." I saw the episode on the Game Show Network a few weeks ago. The guy got it right. He was from Caltech and wound up winning the million. He used all 3 lifelines on a sports question (go figure).</p>
<p>you'll need more info such as the coefficient of expansion and strength of steel</p>