<p>Today in AP Physics Lab, we had a fun discussion about an electric current puzzle called “Bulb Market.” Here it is… you can post you responses. How would you approach and complete your solution?</p>
<p>Houses, boats and cars have electric systems based on 120 V, 24 V, and 12 V respectively. Let’s say we have a 60 watt bulb from each, and enough adapters to plug any bulb into any system. Which combination of bulb and system would give the most light? Which would give the least?</p>
<p>This “fun discussion” is actually your graded lab report that you are trying to cheat on.</p>
<p>We didn’t really do a lab today. We did some practice problems on our textbook (GIANCOLI)'s website. And we don’t have a lab report.</p>
<p>Ok w/e, it’s your extra credit assignment, homework, w/e…I haven’t had physics anyways.</p>
<p>The resistance of the bulb is constant, and it can be found by P = IV and V=IR where P = watts, I = Amps (C/s) and R = ohms (resistance). you can find that P=V^2/R. The greater the power, the brighter the bulb, unless it gets too much power and breaks.</p>