<p>Yeah, it sucks that missing one brings you down to a 77. I missed that one too, but hey, I made a valiant guess...lol, 2/3. It was 3/4. I almost had it by blindly guessing, it was either 2/3 or 3/4, grrr....</p>

<p>**Solution**</p>

<p>In a trapezoid, two sides are parallel, so QS is parallel to PT. That makes angle P and angle Q equal, as well as angle T and angle S. They share angle R. So, by the AAA thingy-majig, triangle QRS and triangle PRT are similar. QR = x, and PR = 2x, so the larger triangle is greater by a factor of two.</p>

<p>I'm preeeeetty sure that this means the heights are also differing by a factor of two. So, the height of the trapezoid is *h*, and the height of the triangle, *2h.* The shorter base of the trapezoid, QS, is *z*, while the longer base of the trapezoid (and base of the triangle PRT) is *2z*. </p>

<p>Area of triangle (obviously): half of base x height</p>

<p>Area of trapezoid (glares daggers at CB for not putting that in there, although I shoulda remembered this): height times (base1 + base2) all over two. </p>

<p>So the area of triangle PRT is 4zh over 2, or 2zh. </p>

<p>The area of the trapezoid is 3zh over 2, or 1.5zh. </p>

<p>Divide the area of the trapezoid by the area of the triangle, and you cancel out all the random variables (z is for zoogie, by the way; don't ask where that came from; h is for height) and are left with 1.5 over 2. Or, 3 over 4.</p>

<p>Damnit, if I only had the stupid trapezoid area formula at the time, I woulda gotten it. It's not like I would have run out of time thinking it out, I had around ten minutes left when I got to that problem.</p>

<p>(By the way, I just did this now...took me a bit, and I still think it's a very cruel problem. They gave you the formula for the area of a *rectangle!* A RECTANGLE! And not a trapezoid. Gaaaaar...)</p>